Answer:
1608.5 cm³
Step-by-step explanation:
Use the cylinder volume formula, V = 
r²h
If the diameter is 16 cm, then the radius is 8 cm.
Plug in the radius and height into the formula, and solve:
V = r²h
V = (8)²(8)
V = (64)(8)
V = 1608.5
So, to the nearest tenth, the volume of the cylinder is 1608.5 cm³
Which page is this in the book
Answer:
The correct option is;
∠AQS ≅ ∠BQS when AS = BS
Step-by-step explanation:
Given that AQ is equal to BQ. When AS is drawn congruent to BS, we have;
QS is congruent to SQ by reflective property
Therefore;
The three sides of triangle QAS are congruent to the three sides of triangle QBS, from which we have;
∠AQS and ∠BQS are corresponding angles, therefore;
∠AQS ≅∠BQS because corresponding angles of congruent triangles are also congruent.
We can solve this problem by using PEMDAS
PEMDAS stands for
Parenthesis
Exponents
Multiply
Add
Subtract
So start with (P+3) () is a parenthesis
Answer:
diameter = m - c
Step-by-step explanation:
In ΔABC, let ∠C be the right angle. The length of the tangents from point C to the inscribed circle are "r", the radius. Then the lengths of tangents from point A are (b-r), and those from point B have length (a-r).
The sum of the lengths of the tangents from points A and B on side "c" is ...
(b-r) +(a-r) = c
(a+b) -2r = c
Now, the problem statement defines the sum of side lengths as ...
a+b = m
and, of course, the diameter (d) is 2r, so we can rewrite the above equation as ...
m -d = c
m - c = d . . . . add d-c
The diameter of the inscribed circle is the difference between the sum of leg lengths and the hypotenuse.
