<u>Answer</u>: No, we do not have sufficient evidence to conclude that the mean call duration, µ, is different from the 2010 mean of 9.4 minutes.
Step-by-step explanation:
As per given , we have
, since
is two-tailed so , the test is a two tail test.
Since population standard deviation is unknown, so we use t-test.
Critical value (two-tailed) for significance level of 0.01=
For n =50 ,
and s= 4.8
Test statistic : 

Since test statistic value (-1.18) lies in critical interval (-2.609228, 2.609228), it means the null hypothesis is failed to reject.
We do not have sufficient evidence to conclude that the mean call duration, µ, is different from the 2010 mean of 9.4 minutes.
The answer would be -13 54/55
Hello,
-2m^3+m²-m+1=(m+1)(-2m²+3m-4) +5
We must add -5 ; the remainder will be 5-5=0.
10 ! (To find the median add the two middle numbers 7,13 = 20 divide 20 by two and you get 10 as your median. Mode means the most common number which means the mode is also 10)
Answer:
0.375
Step-by-step explanation:
..