The equation of line that is parallel to the line 3x-2y=4 and that passes through the point (6, 6) is y=
x-3.
<h3>What is general equation of line?</h3>
A straight line's general equation is y = mx + c, where m denotes the gradient and y = c denotes the point at which the line crosses the y-axis. This value c is referred to as the intercept on the y-axis. y = mx + c is the equation for a straight line with a gradient of m and an intercept of c on the y-axis.
Given that: the line is parallel to the line 3x-2y=4 and that passes through the point (6, 6).
Turn 3x-2y=4 into y= (mx+c) form
Subtract 3x from both sides
-2y = 4 - 3x
Divide -2 from both sides
y= -2+(3/2)x
y= (3/2)x-2
Use slope 3/2 since the line is parallel.
Put point (6, 6) into equation to find c
6=(3/2)(6) + c
6=9 + c
c = -3
Put the value of c in the general equation y= mx+c
y= (3/2)x-3
To learn more about equations of line visits:
brainly.com/question/12203383
#SPJ9
Answer:
CD=14
DE=21
Step-by-step explanation:
ΔCDE is similar to ΔFNE (∠E≅∠E, ∠NFE≅∠DCE) by AA similarity
Using Thales' Intercept Theorem Corollary, you know that:
EN/ED=EF/EC=NF/CD=12/20
Let DN be 8x and NE be 12x
Let NF be 12y and CD be 20y
Then you have a system of equations:
20x+20y+20=55
8x=12y
By solving them, you get y=0.7 and x=1.05⇒
DE=21 and CD=14
We know that
<span>applying the Pythagorean theorem
c</span>²=a²+b²
c is the <span>length of the diagonal
a=100 yd
b=130 yd
c</span>²=100²+130²-------> c²=26900---------> c=√26900 units----> c=10√269 units
the answer is
the length of the diagonal is 10√269 units or 164.012 units