<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em> </em><em>⤴</em>
<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em>
Exact Form:
−1/2, b = 1
-12,b=1
Decimal Form:
−0.5,b=1
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49 divided by 3 = 16.33
Each sibling has about 16 rare coins.
You should be able to multiply 91 by 8 to get the sum of the first 8 tests, then add the score on the 9th test. Then to get the average of the sum of the 9 tests you need to divide it by 9.
((91*8)+78)/9=89.555555555555.... So, 90%
Answer:
a. The arm spans for Class A have more variability than the arm spans for Class B.
Step-by-step explanation:
The stemplot for the Arm span is given for Class A and Class B. The variability of Class A are higher than variability of Class B. The arm spans of Class A have values greater than Class B. The mean of Class A is greater than Class B.