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3 years ago

Can someone plz help me solved this problem! I really need help ASAP! Will mark you as brainiest!

Mathematics

2 answers:

Ivahew [28]3 years ago

6 0

Answer:

a) k = 3 b) k = 4

Step-by-step explanation:

a) 3 x 7 = 21

b) 4 x 3 = 12

pogonyaev3 years ago

5 0

Answer:

1) k=3 (2) k=4

Step-by-step explanation:

$21=k\cdot \:7\quad \\\mathrm{Switch\:sides}\\k\cdot \:7=21\\\frac{k\cdot \:7}{7}=\frac{21}{7}\\k=3\\2)\\12=k\cdot \:3\\Switch\:sides\\k\cdot \:3=12\\\frac{k\cdot \:3}{3}=\frac{12}{3}\\k=4$

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Someone please help me

MAVERICK [17]

Answer:

Step-by-step explanation: 1 foot is 12 inches. Since the feet are going up by ones, you can say 1=12, 2=24 (+12), 3=36(+12), 4=48(+12)

Hope this helps

7 0

3 years ago

Read 2 more answers

The heights of women aged 20 to 29 is approximately Normal with mean 64 inches and standard deviation 2.7 inches. What proportio

natima [27]

20. 64. 2.7
+29 +49 58.6
------ ------ ---------
49. 113 60 .3

49+60.3+113=21.5

4 0

3 years ago

2. CTfastrak bus waiting times are uniformly distributed from zero to 20 minutes. Find the probability that a randomly selected

Juliette [100K]

Answer:

b. 0.25

c. 0.05

d. 0.05

e. 0.25

Step-by-step explanation:

if the waiting time x follows a uniformly distribution from zero to 20, the probability that a passenger waits exactly x minutes P(x) can be calculated as:

$P(x)=\frac{1}{b-a}=\frac{1}{20-0} =0.05$

Where a and b are the limits of the distribution and x is a value between a and b. Additionally the probability that a passenger waits x minutes or less P(X<x) is equal to:

$P(X$

Then, the probability that a randomly selected passenger will wait:

b. Between 5 and 10 minutes.

$P(5$

c. Exactly 7.5922 minutes

$P(7.5922)=0.05$

d. Exactly 5 minutes

$P(5)=0.05$

e. Between 15 and 25 minutes, taking into account that 25 is bigger than 20, the probability that a passenger will wait between 15 and 25 minutes is equal to the probability that a passenger will wait between 15 and 20 minutes. So:

$P(15$