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mario62 [17]
2 years ago
14

Please help me anyone!

Mathematics
1 answer:
alexgriva [62]2 years ago
6 0

Answer:

D

Step-by-step explanation

When it comes to negatives,The closer it is to zero, the higher it is.

Hope this helps, PXL

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In simplest form it should be 5/7
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Janeel has a 10-inch by 12-inch photograph. She wants to scan the photograph, then reduce the result
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<u>Complete Question:</u>

Janeel has a 10 inch by 12 inch photograph. She wants to scan the photograph, then reduce the results by the same amount in each dimension to post on her Web site. Janeel wants the area of the image to be one eight of the original photograph. Write an equation to represent the area of the reduced image. Find the dimensions of the reduced image.

<u>Correct Answer:</u>

A) (10-x)(12-x)=15

B) Dimensions are : Length = 10-x = 3 inch , Breadth = 12-x = 5 inch

<u>Step-by-step explanation:</u>

a. Write an equation to represent the area of the reduced image.

Let the reduced dimensions is by x , So the new dimensions are

length=10-x\\breadth=12-x

According to question , Area of new image is :

⇒ Area = \frac{1}{8}Length(breadth)

⇒ Area = \frac{1}{8}(10)(12)

⇒ Area = 15

So the equation will be :

⇒ (10-x)(12-x)=15

b. Find the dimensions of the reduced image

Let's solve :  (10-x)(12-x)=15

⇒ 120-10x-12x+x^2=15

⇒ 120-22x+x^2=15

⇒ x^2-22x+105=0

By Quadratic formula :

⇒ x = \frac{-b \pm \sqrt{b^2-4ac} }{2a}

⇒ x = \frac{22 \pm8 }{2}

⇒ x = \frac{22 +8 }{2} , x = \frac{22 -8 }{2}

⇒ x = 15 , x =7

x = 15 is rejected ! as 15 > 10 ! Side can't be negative

⇒ x =7

Therefore, Dimensions are : Length = 10-x = 3 inch , Breadth = 12-x = 5 inch

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Answer:

no solution.

Step-by-step explanation:

1) in order to explain, the given system should be resolved:
\left \{ {{2y=6x+4} \atop {y=3x-4}} \right. \ < = > \ \left \{ {{y=3x+2} \atop {y=3x-4}} \right.

2) the both equations have the same slope (it is 3), it means the given lines are parallel, then no solution.

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2 years ago
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