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4vir4ik [10]
4 years ago
14

Please help with this question asap

Mathematics
1 answer:
stepladder [879]4 years ago
3 0

Pythagoras theorem: leg 1 squared + leg 2 squared = hypotenuse squared

In the diagram, the triangle has angles 90 and 45. So the other angle in the triangle must be 45 degrees as well.  (180 - 90 -45 = 45)

This means it is an isosceles triangle (since two angles are the same), so the two legs have the same length.

So we can say that length of leg1 = x, and the length of leg2 also equals x

Now let's use pythagoras' theorem:

leg1 = x

leg2 = x

hypotenuse = 16

x^2 + x^2 = 16^2

      2x^2 = 16^2

      2x^2  = 256

        x^2 = 128

        x = √(128)

        x = 8√2

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what is the equation in slope intercept form of the line that passes through the point (-4,47) and (2,-16)
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The slope-intercept form:

y=mx+b

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (-4, 47) and (2, -16). Substitute:

m=\dfrac{-16-47}{2-(-4)}=\dfrac{-63}{6}=-\dfrac{63:3}{6:3}=-\dfrac{21}{2}

Therefore we have:

y=-\dfrac{21}{2}x+b

Put the coordinates of the point (2, -16) to the equation:

-16=-\dfrac{21}{2}(2)+b\\\\-16=-21+b\qquad\text{add 21 from both sides}\\\\5=b\to b=5

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6 0
3 years ago
Re-write the quadratic function below in Standard Form<br> y = -(x – 4)(x – 7)
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3 0
3 years ago
Find the differential of the function. v = 2y cos(xy)
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Given a function f(x,y), the differential of f is given by
df = f_x dx + f_y dy
where f_x is the derivative of f(x,y) with respect to x, while f_y is the derivative of f(x,y) with respect to y.

The function of our problem isf(x,y)=2y \cos(xy)
The derivative in x is
f_x = 2y(-y \sin (xy))=-2y^2 \sin (xy)
The derivative in y is
f_y = 2 \cos (xy) + 2y (-x \sin (xy))=2 \cos (xy) - 2xy \sin (xy)

So, the differential of f(x,y) is
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4 0
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mars1129 [50]

Answer:

the area of Green band is 576+48x \ in^2.

Step-by-step explanation:

Given:

side length of yellow square = x in

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We need to find the area of the green band.

Solution:

First we will find the area of Yellow square.

area of Yellow square is equal to square of the side length.

framing in equation form we get;

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Now to find the area of the green square we will subtract area of Yellow square from Area of the whole square.

framing in equation form we get;

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6 0
3 years ago
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