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xxMikexx [17]
2 years ago
8

Picture says all 20 charecters needed

Mathematics
2 answers:
Alika [10]2 years ago
7 0

Answers:

Lower bound = 41.3

Upper bound = 41.5

===========================================================

Explanation:

49.15 is the smallest f can be while 49.24 is the largest it can be. Well technically we could have something like 49.2499 or 49.24999 and so on. We slowly approach 49.25 but never actually get there

So the variable f is between 49.15 and 49.25 inclusive of the first value but excluding the second value. We can write it as 49.15 \le f < 49.25

For similar reasoning, 7.75 \le g < 7.85

-----------------

If we wanted to subtract those variables and get the smallest result possible, then we need to pick values that are closest together. It might help to set up a number line.

This means we'd go for f = 49.15 and g = 7.85

The lower bound for f-g is f-g = 49.15-7.85 = 41.3

In contrast, the upper bound is when the two variables are spaced as far apart as possible. The upper bound is f-g = 49.25 - 7.75 = 41.5

photoshop1234 [79]2 years ago
3 0

Answer:

See below

Step-by-step explanation:

49.2     could  be       49.15 <= f < 49.25

7.8        could be       7.75 <= f < 7.85

Lower bound of   f- g    would then be    49.15  - 7.85 > 41.3

upper bound     49.25 - 7.75 < 41.5

<u>  41.3  < f-g < 41.5 </u>

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Answer:

B. 5\times10^{2}

Step-by-step explanation:

We are told that the smallest object visible with our eyes is similar to the width of a piece of hair, which is 1\times 10^{-4} meters wide.

Using an optical microscope, we can see items up to 2\times 10^{-7} meters wide.

To find the objects we can see with our eyes are how much larger than the objects we can see with an optical microscope, we can set an equation as:

\frac{\text{The width of the object we can see with our eyes}}{\text{The width of the objects we can see with microscope}}=\frac{1*10^{-4}}{2*10^{-7}}

Using the exponent rule of quotient \frac{a^m}{a^n}=a^{m-n} we will get,

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\frac{\text{The width of the object we can see with our eyes}}{\text{The width of the objects we can see with microscope}}=0.5*10^{-4+7}

\frac{\text{The width of the object we can see with our eyes}}{\text{The width of the objects we can see with microscope}}=0.5*10^{3}

\frac{\text{The width of the object we can see with our eyes}}{\text{The width of the objects we can see with microscope}}=0.5*10\times 10^{3-1}

\text{The object we can see with our eyes}=5\times10^{2}*\text{The objects we can see with microscope}

Therefore, the objects we can see with our eyes are 5\times10^{2} times larger than the objects we can see with an optical microscope and option B is the correct choice.

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