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Mama L [17]
3 years ago
12

If you guys can figure this out ur a genius

Mathematics
1 answer:
baherus [9]3 years ago
7 0

Answer:

252 ft squared

Step-by-step explanation:

Since the radius of the circle is 3, then the diameter would be 6

Split the rectangle into 3

The way I split the shape is like the picture attached (with the blue lines).

Find the area of each rectangle which can be easily found by using the diameter of each circle (picture attached with black lines)

6*18=108

6*12=72

6*12=72

Add the areas of each rectangle.

108+72+72=252

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six angles of a heptagon measure 107, 139, 131, 110, 145. and 128. what is the measure of the seventh angle​
alexgriva [62]

the measure is 140, I basically summed all of the angles of a polygon of “n”, which is 7, then I did 7-2 times 180 (900) so I can finally add up all of your measurements

3 0
3 years ago
What’s the answer to this?
Rus_ich [418]

Answer:

y = -1/2x + 1

Step-by-step explanation:

Using the slope formula: y = (y2 - y1)/(x2 - x1), we can determine that the slope is -1/2. There is only one answer with the slope of -1/2, but to check that it's right, we can plug in one of the points to see that y = -1/2x + 1 works.

5 0
3 years ago
In a home theater system, the probability that the video components need repair within 1 year is 0.02, the probability that the
earnstyle [38]

Answer:

(a) The probability that at least one of these components will need repair within 1 year is 0.0278.

(b) The probability that exactly one of these component will need repair within 1 year is 0.0277.

Step-by-step explanation:

Denote the events as follows:

<em>A</em> = video components need repair within 1 year

<em>B</em> = electronic components need repair within 1 year

<em>C</em> = audio components need repair within 1 year

The information provided is:

P (A) = 0.02

P (B) = 0.007

P (C) = 0.001

The events <em>A</em>, <em>B</em> and <em>C</em> are independent.

(a)

Compute the probability that at least one of these components will need repair within 1 year as follows:

P (At least 1 component needs repair)

= 1 - P (No component needs repair)

=1-P(A^{c}\cap B^{c}\cap C^{c})\\=1-[P(A^{c})\times P(B^{c})\times P(C^{c})]\\=1-[(1-0.02)\times (1-0.007)\times (1-0.001)]\\=1-0.97216686\\=0.02783314\\\approx 0.0278

Thus, the probability that at least one of these components will need repair within 1 year is 0.0278.

(b)

Compute the probability that exactly one of these component will need repair within 1 year as follows:

P (Exactly 1 component needs repair)

= P (A or B or C)

=P(A\cap B^{c}\cap C^{c})+P(A^{c}\cap B\cap C^{c})+P(A^{c}\cap B^{c}\cap C)\\=[0.02\times (1-0.007)\times (1-0.001)]+[(1-0.02)\times 0.007\times (1-0.001)]\\+[(1-0.02)\times (1-0.007)\times 0.001]\\=0.02766642\\\approx 0.0277

Thus, the probability that exactly one of these component will need repair within 1 year is 0.0277.

7 0
3 years ago
Zane bought 2 packages of candy bars. He had fewer than 22 candy bars. Find b, the number of candy bars in each package.Which in
velikii [3]

Answer:

d

Step-by-step explanation:

the total of two packages (2b) is less than 22

4 0
3 years ago
Write an algebraic expression for 3 times x 2 times x minus 4 times x
Tpy6a [65]

Answer:

(3+2)x - 4x

Step-by-step explanation:

I just converted the words, turned them to operations and that's it!

Hope this helps! :D

- Anna

8 0
3 years ago
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