Answer:
The cone'll require about 37.5 cm of tubing
Step-by-step explanation:
To do this, we need to know that the volume of the medium will have to be the same volume of the cone that will be printed.
Then, the volume of the cone is:
V = π*r^2*h/3
V = 3.14 * 5^2*8 / 3 = 209.33 cm^3
We can assume that the tubing is a cylinder so:
V = π*r^2*h
The radius is 1 1/3, and this is:
1*3 + 1 = 4/3
Solving for h we have:
h= V/π*r^2
h = 209.33 / 3.14*(4/3)^2
h = 209.33 / 5.58
h = 37.5 cm
6.14
9.38
=15.52 ...that is the answer
Ax² + bx + c = 0
2x² + x - 3 = 0
2x² + x + (-3) = 0
x = <u>-b +/- √b² - 4ac</u>
2a
x = <u>1 + /- √1² - 4(2)(-3)</u>
2(2)
x = <u>1 + /- √1 +24</u>
4
x = <u>1 +/- √25
</u> 4<u>
</u>x = <u>1 + /- 5
</u> 4<u>
</u>x = <u>1 + 5</u> x = <u>1 - 5
</u> 4 <u> </u> 4<u>
</u>x = <u>6</u> x = <u>-4</u>
4 4
x = <u>3</u> x = -1
2
x = 1 1/2
x = 1 1/2 x = -1
150 is the answer I hope I’m not wrong sorry if I am
Answer:
Pages: 140, 141
Step-by-step explanation:
divide 281 by 2
281/2 = 140.5
140 + 141 = 281
therefore your pages are 140 and 141