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Verdich [7]
3 years ago
7

Solve 6 times e^0.25t = 9 for t

Mathematics
2 answers:
ICE Princess25 [194]3 years ago
7 0

Answer:

1.62

Step-by-step explanation:

6e^(0.25t) = 9

e^(0.25t) = 1.5

0.25t × lne = ln1.5

0.25t = 0.4054651081

t = 1.6218604324

Svetlanka [38]3 years ago
3 0

Answer:

t =1.621860432

Step-by-step explanation:

6e^0.25t = 9

Divide each side by 6

6/6e^0.25t = 9/6

e^0.25t = 3/2

Take the ln of each side

ln e^0.25t =  ln (3/2)

.25t = ln (3/2)

Divide each side by .25

.25t/.25 = 1/.25 ln (3/2)

t = 4 ln (3/2)

t =1.621860432

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Answer:

The minimum diameter of the cylindrical tank needed to store the quantity needed to put out the fire is approximately 58.415 feet.

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Q = \dot Q \cdot \Delta t (1)

Where:

\dot Q - Volume rate, measured in feet per minute.

\Delta t - Time, measured in minutes.

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And the diameter of the cylindrical tank based on the capacity found above is determined by volume formula for a cylinder:

Q = \frac{\pi}{4}\cdot D^{2}\cdot h (2)

Where:

D - Diameter, measured in feet.

h - Height, measured in feet.

If we know that Q = 32160\,ft^{3} and h = 12\,ft, then the minimum diameter is:

D^{2} = \frac{4\cdot Q}{\pi\cdot h}

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D = 2\cdot \sqrt{\frac{32160\,ft^{3}}{\pi\cdot (12\,ft)} }

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A. dashed line, shade below
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Step-by-step explanation:

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