2 students appeared at an examination, one of

Suppose you drop a tennis ball from a height of 15 feet.

kiruha [24]

9.2 feet

Hope this helps.

Brainliest plz

4 0

2 years ago

Katy wants to sell her car, which she bought six years ago for $35,000. Since then, the value of the car has depreciated and it

alekssr [168]

A negative correlation: when the number of years increase the value of the car decrease.

8 0

3 years ago

College freshmen took a psychology exam. If the mean is 80, the SD is 10, and the scores have normal distribution, what percent

gayaneshka [121]

Answer:

(a) 2%

Step-by-step explanation:

A score of 60 is 2 standard deviations below the mean (80 -2·10 = 60). The empirical rule tells you that 95% of the distribution is within 2 standard deviations of the mean. The remaining 5% is split evenly between those that are more than 2 SD above the mean and those that are more than 2 SD below the mean.

That tells you the percentage who failed is about 2.5%. The best answer choice is 2%.

_____

<em>Additional comment</em>

The empirical rule is a little bit sloppy, but it gets you in the ballpark. The actual percentage is closer to 2.275%.

6 0

2 years ago

Jen has 6 yards of fabric and wants to make a new dress and shorts she used 3 1/3 yards of the fabric on her new dress how much

kodGreya [7K]

Answer:

$2\frac{2}{3}\ yards$

Step-by-step explanation:

we know that

To find out how much fabric Jen has left for the shorts, subtract the yards of fabric used in her new dress from the total yards of fabric Jen has.

so

$6-3\frac{1}{3}$

Convert mixed number to an improper fraction

$3\frac{1}{3}=\frac{3*3+1}{3}=\frac{10}{3}$

substitute

$6-3\frac{1}{3}=6-\frac{10}{3}=\frac{8}{3}\ yards$

Convert to mixed number

$\frac{8}{3}\ yards=\frac{6}{3}+\frac{2}{3}=2\frac{2}{3}\ yards$

5 0

3 years ago

A bakery works out a demand function for its chocolate chip cookies and finds it to be q = D (x) = 943 - 17 x, where q is the q

Alex73 [517]

Answer:

See expla below

Step-by-step explanation:

Given the demand function:

q = D (x) = 943 - 17 x

a) Find the elasticity:

Find the derivative of the demand function.

D'(x)= -17

Thus, elasticity expression is:

$\frac{x D'(x)}{D'(x)}$

$= \frac{x (-17)}{943 - 17x}$

$= \frac{17x}{943 - 17x}$

Elasticity expression = $E(x) = \frac{17x}{943 - 17x}$

b) At what price is the elasticity of demand equal to 1?

This means E(x) = 1

Substitute 1 for E(x) in the elasticity equation:

$E(x) = \frac{17x}{943 - 17x}$

$1 = \frac{17x}{943 - 17x}$

Cross multiply:

$943 - 17x = 17x$

Collect like terms

$17x + 17x = 943$

$34x = 943$

$x = \frac{943}{34}$

x = 27.74

Elasticity at the price of demand = 1 is 27.74

c) At what prices is the elasticity of demand elastic?

This means E(x) > 1

Therefore,

$\frac{17x}{943 - 17x} > 1$

Cross multiply:

$17x > 943 - 17x$

Collect like terms

$17x + 17x > 943$

$34x > 943$

$x > \frac{943}{34}$

x > 27.74

The elasticity of demand is elastic at x > 27.74

d) At what prices is the elasticity of demand inelastic?

This means E(x) < 1

Therefore,

$\frac{17x}{943 - 17x} < 1$

Cross multiply:

$17x < 943 - 17x$

Collect like terms

$17x + 17x < 943$

$34x < 943$

$x < \frac{943}{34}$

x < 27.74

The elasticity of demand is inelastic at x < 27.74

e) At what price is the revenue a maximum:

Total revenue will be:

R(x) = x D(x)

= x (943 - 17x)

= 943x - 17x²

R(x) = 934 - 17x(price that maximizes total revenue)

Take R(x) = 0

Thus,

0 = 943 - 17x

17x = 943x

$x = \frac{943}{17}$

$x = 27.74$

Total revenue is maximun at x= 27.74 per cookie

f) At x = 21 per cookie, find the price:

Thus,

R (21) = (943 * 21) - (17 * 21²)

= 19803 - 7497

= 12306

At x = 27.74, find the price:

R(27.74) = (943 * 27.74) - (17 - 27.74²)

= 26158.82 - 13081.63

= 13077.19

We can see the new price of cookie causes the total revenue to decrease.

Therefore, with a small increase in price the total revenue will decrease.

5 0

3 years ago