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bixtya [17]
4 years ago
14

In a coin collection,the number of dimes is 6 more than twice the number of nickels if the collection has 36 dimes how many nick

els are in the collection
Mathematics
2 answers:
gulaghasi [49]4 years ago
4 0
15 nickels, hope this helps :)
-BARSIC- [3]4 years ago
4 0
15 nickles! i hope thats how you spell nickles lol
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The complete factorized expression is (2 + 2a + 3b) (2 - 2a + 3b).
Take a look at the attachment to see how I got this solution. 

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3 years ago
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The chief chemist for a major oil and gasoline production company claims that the regular unleaded gasoline produced by the comp
Svetradugi [14.3K]

Answer:

The probability of finding an average in excess of 4.3 ounces of this ingredient from 100 randomly inspected 1-gallon samples of regular unleaded gasoline = P(x > 4.3) = 0.00621

Step-by-step explanation:

This is a normal distribution problem

The mean of the sample = The population mean

μₓ = μ = 4 ounces

But the standard deviation of the sample is related to the standard deviation of the population through the relation

σₓ = σ/√n

where n = Sample size = 100

σₓ = 1.2/√100

σₓ = 0.12

The probability of finding an average in excess of 4.3 ounces of this ingredient from 100 randomly inspected 1-gallon samples of regular unleaded gasoline = P(x > 4.3)

To do this, we first normalize/standardize the 4.3 ounces

The standardized score for any value is the value minus the mean then divided by the standard deviation.

z = (x - μ)/σ = (4.3 - 4)/0.12 = 2.5

To determine the probability of finding an average in excess of 4.3 ounces of this ingredient from 100 randomly inspected 1-gallon samples of regular unleaded gasoline = P(x > 4.3) = P(z > 2.5)

We'll use data from the normal probability table for these probabilities

P(x > 4.3) = P(z > 2.5) = 1 - P(z ≤ 2.5) = 1 - 0.99379 = 0.00621

5 0
3 years ago
Name an event that would be measured in days
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8 0
3 years ago
Read 2 more answers
Two forces with magnitudes of 150 and 100 pounds act on an object at angles of 30° and 120°, respectively. Find the direction an
lyudmila [28]
<h2>Answer:</h2>

Magnitude=180.27 \ lbf \\ \\ Direction=63.69 \ degrees

<h2>Step-by-step explanation:</h2>

We have two forces as follows:

<u>First force:</u>

Magnitude: 150 pounds

Angle: 30°


<u>First force:</u>

Magnitude: 100 pounds

Angle: 120°


So the components can be found as follows:

F_{1x}=150cos(30)=129.90 \ lbf\\F_{1y}=150sin(30) = 75 \ lbf \\ \\ F_{2x}=100cos(120)=-50 \ lbf\\F_{2y}=100sin(120) = 86.60 \ lbf


So the components of the resultant force can be found by adding each component of the individual forces as follows:

R_{x}=\Sigma F_{x} \\ R_{y}=\Sigma F_{y} \\ \\ R_{x}=129.90-50=79.90 \ lbf \\ R_{y}=75+86.60=161.6 \ lbf


Finally, the magnitude and direction of the resultant force is:

Magnitude \rightarrow R=\sqrt{R_{x}^2+R_{y}^2}=\sqrt{79.90^2+161.6^2}=180.27 \ lbf \\ \\ Direction \rightarrow \theta=tan^{-1}(\frac{R_{y}}{R_{x}})=tan^{-1}(\frac{161.6}{79.90})=63.69 \ degrees

6 0
3 years ago
Read 2 more answers
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