Use algebra to evaluate the following limit ((3+h)^2-9)/h

Please answer thanks! :)

Lana71 [14]

I believe she messed up in Step 2, it wouldnt be 7/8 it would be 6/8

8 0

3 years ago

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. A biologist estimated that there were 5500 fish in a lake in which 250 fish had been tagged

lana66690 [7]

Answer:

250 tagged 5500 total = 15 tagged x total x=330 fish were sampled.

Step-by-step explanation:

A biologist estimated that there were 5500 fish in a lake in which 250 fish had been tagged. A ranger collected a sample in which there were 15 tagged fish. Approximately how many fish were in the sample the ranger collected?

7 0

4 years ago

y = x2 − 6x 8 2y x = 4 the pair of points representing the solution set of this system of equations is___ and ___?

mariarad [96]

Some operators are missing.
If the right equations are y = x^2 -6x +8 and 2y + x =4
This is the solution

2y + x = 4
2y = -x +4
y = -x/2 + 2

y = x^2 -6x + 8 = -x/2 + 2

2x^2 - 12x + 16 = -x + 4
2x^2 -11x +12 = 0

Factor

(x-4)(2x-3)=0

x= 4 and x =3/2

y = -x/2 +2

y = -4/2 + 2 = 0
y = - (3/2)/2 + 2 = -3/4 + 2 = 5/4

Answer (4,0) and (3/2, 5/4)

3 0

3 years ago

The equation below shows the relationship between the temperature in degrees Celsius, C, and degrees Fahrenheit, F:

algol [13]

Th first answer
F = 9 over 5 C + 32

5 0

3 years ago

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A master painter can paint 110 square yards of surface area with a roller in 1 hour, while his apprentice can paint 85 square fe

7nadin3 [17]

The apprentice needs 6.25 hours to complete the job using the brush

<h3><u>Solution:</u></h3>

Given, A master painter can paint 110 square yards of surface area with a roller in 1 hour

$\text { Then, his rate of painting }=110 \text { yard }^{2}$

We know that 1 yard = 3 feet

$=110 \times(1 \text { yard })^{2}=110 \times(3 \text { feet })^{2}=110 \times 9 \text { feet }^{2}=990 \text { square feet. }$

While his apprentice can paint 85 square feet of surface area per hour with a brush

Together they are painting a building with a surface area of 5100 square feet.

After painting for $4\frac{1}{4}$ hours , the master painter lets the apprentice Finish the job.

Now, they worked for $4\frac{1}{4}$ hours

Then, area painted = area painted by master + area painted by apprentice

$\text { Area painted }=990 \text { square feet per hour } \times 4 \frac{1}{4} \text { hours }+85 \text { square feet per hour } \times 4 \frac{1}{4} \text { hours }$

$\text { Area painted }=990 \times \frac{4 \times 4+1}{4}+85 \times \frac{4 \times 4+1}{4}$

$\begin{array}{l}{\text { Area painted }=990 \times \frac{17}{4}+85 \times \frac{17}{4}=(990+85) \times \frac{17}{4}} \\\\ {\text { Area painted }=1075 \times \frac{17}{4}=4568.75 \text { square feet. }}\end{array}$

Now, the remaining area to be painted = total area – painted area

Area to be painted = 5100 – 4568.75 = 531.25

So, apprentice has to paint 531.25 square feet alone.

$\text { Then, time required }=\frac{\text { area to be painted }}{\text { his rate of painting }}$

$=\frac{531.25}{85}=6.25$

Hence, the apprentice needs 6.25 hours to complete the job

7 0

4 years ago