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kozerog [31]
3 years ago
10

Which direction would the graph of y=-|x+2|+3 open?

Mathematics
2 answers:
romanna [79]3 years ago
5 0
This is it, it will open down :)

miskamm [114]3 years ago
4 0

Answer:

The absolute function opens in downward direction.

Step-by-step explanation:

we have to find the direction in which the graph of y=-|x+2|+3 open.

The general form of an absolute value function is f(x)=a|x-h|+k.

The absolute value function will always open to the negative direction when a is negative and positive direction i.e upward when a is positive.

Here, given absolute function is y=-|x+2|+3

which gives a=-1, negative

Hence, the absolute value function will always open to the negative direction. Because this is in the form y = -|x|, it opens down.

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fredd [130]
<h3>Answer: Choice B</h3>

Angle 1 = 147 degrees

Angle 2 = 80 degrees

Angle 3 = 148 degrees

======================================================

Work Shown:

(angle 1) + 33 = 180

angle 1 = 180-33

angle 1 = 147 degrees

---------------

Focus on the left most triangle that has angles 33 and 47 as interior angles. The missing angle is 180-33-47 = 100 degrees

The angle exterior to this 100 degree angle is angle 2

angle 2 = 180-100 = 80

We have enough info to conclude the answer must be choice B.

---------------

Let's keep going to find angle 3

The vertical angle for the 100 degree angle is also 100 degrees. This second 100 degree angle is part of the triangle on the right

This triangle on the right has interior angles 100 and 48

The missing interior angle is 180-100-48 = 32

The angle supplementary to this is 180-32 = 148, which is angle 3.

5 0
3 years ago
What is the value of a? <br><br>A.-16<br>B.-3<br>C.3<br>D.16​
Igoryamba

Answer:

Which equation do I refer to?

Step-by-step explanation:

7 0
1 year ago
Find the area of the parallelogram with vertices:________.
marin [14]

Answer:

97.98

Step-by-step explanation:

The area of the parallelogram PQR is the magnitude of the cross product of any two adjacent sides. Using PQ and PS as the adjacent sides;

Area of the parallelogram = |PQ×PS|

PQ = Q-P and PS = S-P

Given P(0,0,0), Q(4,-5,3), R(4,-7,1), S(8,-12,4)

PQ = (4,-5,3) - (0,0,0)

PQ = (4,-5,3)

Also, PS = S-P

PS = (8,-12,4)-(0,0,0)

PS = (8,-12,4)

Taking the cross product of both vectors i.e PQ×PS

(4,5,-3)×(8,-12,4)

PQ×PS = (20-36)i - (16-(-24))j + (-48-40)k

PQ×PS = -16i - 40j -88k

|PQ×PS| = √(-16)²+(-40)²+(-88)²

|PQ×PS| = √256+1600+7744

|PQ×PS| = √9600

|PQ×PS| ≈ 97.98

Hence the area of the parallelogram is 97.98

3 0
3 years ago
Anyone know this? algebra 1 is so hard LOL
musickatia [10]

Answer:

Y= 2x+3

Step-by-step explanation:

The slope of two parallel lines are always the same.

8 0
2 years ago
What project did mary jackson work on at naca soon after she was hired?.
saw5 [17]
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