All categories

1 year ago

B + 1.5 = 6 solve the equation and find the value of the variable

Mathematics

2 answers:

pickupchik [31]1 year ago

5 0

The answer is 4.5. Because 6 minus 1.5 is equal to 4.5

guapka [62]1 year ago

5 0

Answer:

$\boxed{\sf{b=4.5}}$

Step-by-step explanation:

To find the value of variable, you have to isolate the term of b from one side of the equation.

First, you subtract by 1.5 from both sides.

→ b+1.5-1.5=6-1.5

Solve.

Subtract the numbers from left to right.

⇒ 6-1.5=4.5

⇒ b=4.5

Therefore, the correct answer is b=4.5.

I hope this helps you! Let me know if my answer is wrong or not.

You might be interested in

Salinda borrowed $4,200 to buy some furniture Her monthly payments over four years with an interest rate of 24 percent are $136.

Serga [27]

Answer:

1008

Step-by-step explanation:

All you have to do is find what 24 percent of 4200 is.

3 0

2 years ago

What is the missing output value in the function table below

elena-s [515]

Answer:

Step-by-step explanation:

It makes sense because it goes down one by one in both the input and output values

8 0

2 years ago

Point C is located at (1, 2), and point D is located at (-4,-2). Find the point that is the distance from point C

marishachu [46]

Answer:

The answer would be c

Step-by-step explanation:

i choosed c because u have da negative sign in front of 4 and 2 and positive numbers with 1 and 2

6 0

2 years ago

Read 2 more answers

Find the exact value of each trigonometric function for the given angle θ.

Kay [80]

Answer:

$\sin (240^\circ)=-\dfrac{\sqrt{3}}{2},\cos (240^\circ)=-\dfrac{1}{2},\tan (240^\circ)=\sqrt{3},\cot (240^\circ)=\dfrac{1}{\sqrt{3}},\sec (240^\circ)=-2,\csc (240^\circ)=\dfrac{2}{\sqrt{3}}.$

Step-by-step explanation:

The given angle is 240 degrees.

We need to find the exact value of each trigonometric function for the given angle θ.

Since $\theta=240$ , it means θ lies in 3rd quadrant. In 3d quadrant only tan and cot are positive.

$\sin (240^\circ)=\sin (180^\circ+60^\circ)=-\sin (60^\circ)=-\dfrac{\sqrt{3}}{2}$

$\cos (240^\circ)=\cos (180^\circ+60^\circ)=-\cos (60^\circ)=-\dfrac{1}{2}$

$\tan (240^\circ)=\tan (180^\circ+60^\circ)=\tan (60^\circ)=\sqrt{3}$

$\cot (240^\circ)=\cot (180^\circ+60^\circ)=\cot (60^\circ)=\dfrac{1}{\sqrt{3}}$

$\sec (240^\circ)=\sec (180^\circ+60^\circ)=-\sec (60^\circ)=-2$

$\csc (240^\circ)=\csc (180^\circ+60^\circ)=-\csc (60^\circ)=-\dfrac{2}{\sqrt{3}}$

Therefore, $\sin (240^\circ)=-\dfrac{\sqrt{3}}{2},\cos (240^\circ)=-\dfrac{1}{2},\tan (240^\circ)=\sqrt{3},\cot (240^\circ)=\dfrac{1}{\sqrt{3}},\sec (240^\circ)=-2,\csc (240^\circ)=-\dfrac{2}{\sqrt{3}}.$

8 0

2 years ago

List all number sets that apply to each number

kolbaska11 [484]

Answer:

224

Step-by-step explanation:

5 0

3 years ago