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Alik [6]
3 years ago
9

Malia is placing a barrier around the edge of a circular path with a diameter of 13 m. The barriers are in lengths of 2.5 m.

Mathematics
2 answers:
icang [17]3 years ago
8 0

Answer: 17 is the answer

Can I get brainliest pls

Rufina [12.5K]3 years ago
7 0
Circumference=2 x pi x radius
diameter=13, so 13/2=6.5=radius

2 x 3.14 x 6.5=40.82m around.
 40.82/2.5(length of each piece)= 16.33 or 17 pieces needed.
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Every time I use a piece of scrap paper, I crumple it up and try to shoot it inside the recycling bin across the room. I'm prett
valentinak56 [21]

Using the binomial distribution, it is found that there is a 0.0012 = 0.12% probability at least two of them make it inside the recycling bin.

<h3>What is the binomial distribution formula?</h3>

The formula is:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
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  • p is the probability of a success on a single trial.

With 5 shoots, the probability of making at least one is \frac{211}{243}, hence the probability of making none, P(X = 0), is \frac{232}{243}, hence:

(1 - p)^5 = \frac{232}{243}

\sqrt[5]{(1 - p)^5} = \sqrt[5]{\frac{232}{243}}

1 - p = 0.9908

p = 0.0092

Then, with 6 shoots, the parameters are:

n = 6, p = 0.0092.

The probability that at least two of them make it inside the recycling bin is:

P(X \geq 2) = 1 - P(X < 2)

In which:

[P(X < 2) = P(X = 0) + P(X = 1)

Then:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{6,0}.(0.0092)^{0}.(0.9908)^{6} = 0.9461

P(X = 1) = C_{6,1}.(0.0092)^{1}.(0.9908)^{5} = 0.0527

Then:

P(X < 2) = P(X = 0) + P(X = 1) = 0.9461 + 0.0527 = 0.9988

P(X \geq 2) = 1 - P(X < 2) = 1 - 0.9988 = 0.0012

0.0012 = 0.12% probability at least two of them make it inside the recycling bin.

More can be learned about the binomial distribution at brainly.com/question/24863377

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