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zubka84 [21]
3 years ago
10

Which of the following best describes the diameter of a circle

Mathematics
2 answers:
inysia [295]3 years ago
6 0

Answer:

You need more info

Step-by-step explanation:

It does not give any files

WITCHER [35]3 years ago
6 0
Add two to the radius
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A swimming pool measures 35 feet wide by 50 feet long. What is the ratio of the length to the perimeter in simplest form?
seropon [69]

Answer:

i think it is 5:17

Step-by-step explanation:

length=50

perimeter=170

the highest factor of 50 and 170 is 10 so the answer will be 5:17

hopefully this made sense

6 0
3 years ago
Write the equation of the line that passes through (2, 4) and has a slope of –1 in point-slope form.
Tems11 [23]
Y - y1 = m(x - x1).....this is point slope form
slope(m) = -1
(2,4)...x1 = 2 and y1 = 4
now we sub
y - 4 = -1(x - 2) <===
3 0
4 years ago
ASAPPP 80 POINTSS How many times as large as the radius of a hydrogen atom are the radii of the mercury and the radii of the ura
Fittoniya [83]

Answer:

divide 1.5x10^-10 by 2.5x10^-11 which is 6 meaning the Mercury atom is 6 times larger than a hydrogen atom.

Step-by-step explanation:

im sure thats right !

3 0
3 years ago
Read 2 more answers
What is the range of f(x) = (three-fourths) Superscript x – 4?
murzikaleks [220]
{y | y > –4}



Left-brace y vertical line y greater-than three-fourths right-brace



{y | y < –4}



Left-brace y vertical line y less-than three-fourths right-brace
8 0
3 years ago
WILL MARK BRAINLIEST <br><br> what is the domain of (f/g) (x)?
tatyana61 [14]

Given that f(x) = \sqrt{7-x} and g(x) = \sqrt{x + 2}, we can say the following:

\Bigg(\dfrac{f}{g}\Bigg)(x) = \dfrac{f (x)}{g(x)} = \dfrac{\sqrt{7 - x}}{\sqrt{x+2}}


Now, remember what happens if we have a negative square root: it becomes an imaginary number. We don't want this, so we want to make sure whatever is under a square root is greater than 0 (given we are talking about real numbers only).


Thus, let's set what is under both square roots to be greater than 0:

\sqrt{7 - x} \Rightarrow 7 - x \geq 0 \Rightarrow x \leq 7

\sqrt{x + 2} \Rightarrow x + 2 \geq 0 \Rightarrow x \geq -2


Since both of the square roots are in the same function, we want to take the union of the domains of the individual square roots to find the domain of the overall function.

x \leq 7 \,\,\cup x \geq -2 = \boxed{-2 \leq x \leq 7}


Now, let's look back at the function entirely, which is:

\Bigg( \dfrac{f}{g} \Bigg)(x) = \dfrac{\sqrt{7 - x}}{\sqrt{x+2}}

Since \sqrt{x + 2} is on the bottom of the fraction, we must say that \sqrt{x + 2} \neq 0, since the denominator can't equal 0. Thus, we must exclude \sqrt{x + 2} = 0 \Rightarrow x + 2 = 0 \Rightarrow x = -2 from the domain.


Thus, our answer is Choice C, or \boxed{ \{ x | -2 < x \leq 7 \}}.


<em>If you are wondering why the choices begin with the x | symbol, it is because this is a way of representing that x lies within a particular set.</em>

6 0
3 years ago
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