Answer:
The factors of 2q²-5pq-2q+5p are (2q-5p) (q-1)....
Step-by-step explanation:
The given expression is:
2q²-5pq-2q+5p
Make a pair of first two terms and last two terms:
(2q²-5pq) - (2q-5p)
Now factor out the common factor from each group.
Note that there is no common factor in second group. So we will take 1 as a common factor.
q(2q-5p) -1(2q-5p)
Now factor the polynomial by factoring out the G.C.F, 2q-5p
(2q-5p) (q-1)
Thus the factors of 2q²-5pq-2q+5p are (2q-5p) (q-1)....
Answer:
0.055
Step-by-step explanation:
You want to move the decimal from the % left two places.
Answer:
every difference x-y is the same for related pairs of x and y
Solve the equation using the quadratic formula
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The Quadratic formula provides the solution for
A
n
2
+
B
n
+
C
=
0
, in which A, B and C are numbers (or coefficients), as follows:
So it would be either n= -5.127 or n= 12.873
