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3 years ago

Bruh i need help please someone help...-halia beamer

Mathematics

2 answers:

Leni [432]3 years ago

8 0

d but I am not to sure

masya89 [10]3 years ago

3 0

D.
- Professor Bextem

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What location on the line would you find the constant of proportionality?

juin [17]

Answer:

2.4

Step-by-step explanation:

The constant of proportionality is y=kx which should 2.4

3 0

2 years ago

Find the missing lengths of the sides

Ket [755]

ANSWER

The correct answer is C

EXPLANATION

The given triangle is a right triangle. Since two angles are equal, it is a right isosceles triangle.

This implies that, x=8 units.

Using Pythagoras Theorem,

${y}^{2} = {8}^{2} + {8}^{2}$

This implies that:

${y}^{2} = 64 + 64$

${y}^{2} =128$

Take positive square root,

${y} = \sqrt{128}$

${y} = 8 \sqrt{2}$

The correct answer is C

5 0

3 years ago

Read 2 more answers

A forestal station receives the locations of two fires, one of them in a forest located 11 Km heading N69°W from the station. Th

loris [4]

Answer:

30.7 km

Step-by-step explanation:

The distance between the two fires can be found using the Law of Cosines. For ΔABC in which sides 'a' and 'b' are given, along with angle C, the third side is ...

c = √(a² +b² -2ab·cos(C))

The angle measured between the two fires is ...

180° -(69° -35°) = 146°

and the distance is ...

c = √(11² +21² -2(11)(21)cos(146°)) ≈ √945.015

c ≈ 30.74

The straight-line distance between the two fires is about 30.7 km.

8 0

2 years ago

Exterior Angles of A Triangle

gladu [14]

The exterior angle is supplementary to the adjacent angle (they form a linear pair) and is the sum of the two angles in the triangle that are not adjacent to it. For example, in number 2, the exterior angle is 28+40=68 degrees. You can use the other method to check. 68 degrees is supposed to be in a linear pair with 112 degrees, which it is. So the answer to number 2 would be 68 degrees.

Try doing this for the rest of them

7 0

2 years ago

What are the steps to solving this limit?

patriot [66]

Answer:

lim(x---->0) = -5

Step-by-step explanation:

first: sin(x-π/2)= -cosx

so the equation will be :

lim(x---->0) = [-6cos(ax)-1}/cosx

solve :

lim(x---->0) = [-(6cos(a(0))-1}/cos(0)

cos0=1

lim(x---->0)=(-(6(1)-1)/1

lim(x---->0)=-6+1/1

lim(x---->0)=-5

6 0

3 years ago

Read 2 more answers