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Alex787 [66]
3 years ago
12

Bruh i need help please someone help...-halia beamer

Mathematics
2 answers:
Leni [432]3 years ago
8 0

d but I am not to sure


masya89 [10]3 years ago
3 0
D. 
- Professor Bextem
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A games shop sells marbles
Taya2010 [7]
To start, the question is asking for surface area of a cylinder, meaning you will have to use this formula to find it: A=2πrh+2πr^2.

Since you already know that the diameter of the plastic cylinder is 4 marbles long, and each marble is 2 cm in diameter, you would multiply 4 and 2 to get that your diameter is 8 cm. However, since the surface area of a cylinder formula uses radius, you would simply divide 8 by 2 to get that the radius of the cylinder is 4 cm. 

Now, since you already know that the height of the cylinder is equal to 10 marbles, multiply the amount of marbles by 2 to get that the height of the cylinder is 20 cm. 

Now that you know the height and the diameter of the cylinder, plug the values into the formula: A=2π(4)(20)+2π(4)^2.
Assuming that pi is 3.14, simplify the equation as according to PEMDAS and you get that the area of plastic needed to make one cylinder is 602.88 cm squared
5 0
4 years ago
5 x - 2y equals 10 ; (3,-5)
Sedbober [7]
5(3)-2(-5)
15-(-10)
25
5 0
3 years ago
What is the answer for this problem number 6 and how do you do it
EleoNora [17]
So you need to add up all the points he scored.  
The mean is the average.  Divide the total by the number of games he played.
6 0
4 years ago
If it takes
Zinaida [17]
1.2 acres could be planted with this much seed
3 0
3 years ago
The point (1,-1) is on the terminal side of angle theta in standard position what are the values of sine cuisine and tangent of
pickupchik [31]
\bf \textit{terminal point }\implies 
\begin{array}{lclcll}
(&1&,&-1)\\
&\uparrow &&\uparrow \\
&x&&y
\end{array}
\\\\\\
sin(\theta)=\cfrac{y}{r}
\qquad 
% cosine
cos(\theta)=\cfrac{x}{r}
\qquad 
% tangent
tan(\theta)=\cfrac{y}{x}\\\\
-----------------------------\\\\
\textit{so, what's the radius "r"?}\implies r^2=x^2+y^2\implies r=\sqrt{x^2+y^2}
3 0
3 years ago
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