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LenaWriter [7]
4 years ago
9

PLEASE HELP , REWARD WILL BE GIVEN

Mathematics
1 answer:
torisob [31]4 years ago
5 0
Total 60 vaccinations that consisted of 184 doses.
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2.15 X 58 = ? (please do an explanation too)
sashaice [31]

Answer:

124.7

Step-by-step explanation:

Calculator

5 0
3 years ago
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In a class of 32 students the mean height of the boys is 1.56 metres
mart [117]

Answer: JW.org is where you can find your answers.

5 0
4 years ago
Colby baked 14 cookies on Saturday. On both Saturday and Sunday, he baked a total of 36 cookies. Which of the following equation
alisha [4.7K]

Answer:

d

Step-by-step explanation:

what he baked on saturday plus what he baked on sunday equals what he baked in all

3 0
3 years ago
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2 number cubes are rolled. (a) List the sample space. (b)What is the probability, as a simplified fraction, that the sum of the
melomori [17]

Solution:

When two number cubes  are rolled,

Sample space= Total Possible outcome {11,22,33,44,55,66,12,21,13,31,14,41,15,51,16,61,23,32,24,42,25,52,26,62,34,43,35,53,36,63,45,54,46,64,56,65}=36

Probability of an event = \frac{\text{Total favorable outcome}}{\text{Total possible outcome}}

Sum of 4 is obtained when ={13,31,22}=3

Probability of getting 4 when 2 number cubes are rolled= \frac{3}{36}=\frac{1}{12}

Sum of the numbers is greater than 9= 10, 11,12={55,64,46,56,65,66}=6

Probability of getting(Sum of the numbers is greater than 9)=\frac{6}{36}=\frac{1}{6}



7 0
4 years ago
There are 50 deer in a particular forest. The population is increasing at a rate of 15% per year. Which exponential growth funct
NemiM [27]

Answer:

The expression that represents the number of deer in the forest is

y(x) = 50*(1.013)^x

Step-by-step explanation:

Assuming that the number of deer is "y" and the number of months is "x", then after the first month the number of deer is:

y(1) = 50*(1+ 0.15/12) = 50*(1.0125) = 50.625

y(2) = y(1)*(1.0125) = y(0)*(1.0125)² =51.258

y(3) = y(2)*(1.0125) = y(0)*(1.0125)³ = 51.898

This keeps going as the time goes on, so we can model this growth with the equation:

y(x) = 50*(1 - 0.15/12)^(x)

y(x) = 50*(1.013)^x

8 0
3 years ago
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