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Amiraneli [1.4K]
2 years ago
14

Jello someone help is this correct answer No links or files Correct answer please

Mathematics
1 answer:
Dvinal [7]2 years ago
5 0

Answer:

c is the right answer

Step-by-step explanation:

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Centimeters and meters size of window
Gnom [1K]

Answer:

Tiff, hon, just measure a window, your wasting your time

Step-by-step explanation:

7 0
3 years ago
Missing factors to find the given estimated product of 6,397×349​
Vlad1618 [11]

Answer:

The answer is 2232553

7 0
3 years ago
What is the solution to the equation 3/m+3-m/3-m=m^2+9/m^2-9
Bas_tet [7]

Answer:

  no solution

Step-by-step explanation:

If we subtract the left side of the equation, we get ...

  \dfrac{m^2+9}{m^2-9}-\dfrac{3}{m+3}+\dfrac{3}{3-m}=0\\\\\dfrac{m^2+9-3(m-3)-3(m+3)}{(m-3)(m+3)}=0\\\\\dfrac{m^2-6m+9}{(m-3)(m+3)}=0=\dfrac{(m-3)^2}{(m-3)(m+3)}\\\\\dfrac{m-3}{m+3}=0\quad\text{m$\ne$3}

This equation will equal zero only if m=3, which is disallowed because it makes the denominator zero. Thus, there is no solution.

7 0
3 years ago
. A hat contains 100 coins, where 99 are fair but one is double-headed (always landing Heads). A coin is chosen uniformly at ran
SOVA2 [1]

Answer:0.565

Step-by-step explanation:

Hat contain 100 coins out of which 99 is fair and one is double headed.

Probability of getting 7 heads is sum of Head through fair coin+heads through biased coin

Probability of getting a head through a fair coin=0.5

P(7 heads)=0.99\times 0.5^7+0.01\times 1

P(Double head |7 heads )=\frac{Probability\ of\ 7\ heads\ and\ double\ headed}{probability\ of\ 7\ heads}

P(Double head |7 heads )=\frac{0.01\times 1}{0.99\times 0.5^7+0.01\times 1}

=\frac{0.01}{0.99\times 0.0078+0.01}=0.565

8 0
3 years ago
In 2014, there were 16,400 students at College A, with a projected enrollment increase of 640 students per year. In the same yea
zhenek [66]

Answer:

4 Years

Step-by-step explanation:

I just continually added the numbers til' I got 18,960 on Both Colleges.

8 0
2 years ago
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