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Usimov [2.4K]
3 years ago
6

A total of 3 ¼ cups of sugar was used for making cookies. Each batch of cookies require ¾ cups of sugar. How many batches of coo

kies were made?
Mathematics
1 answer:
Troyanec [42]3 years ago
3 0
About 3 batches of cookies were made
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What is the midpoint of -5,2 and 1,5
ANEK [815]

Answer:(-2,3.5)

Step-by-step explanation: Add the endpoints and divide by two for the x-values and the y-values

4 0
3 years ago
Find the highest common factor of 55 and 605
Arlecino [84]

Answer:

55

Step-by-step explanation:

Factors for 605: 1, 5, 11, 55, 121, and 605

Factors for 55: 1, 5, 11, and 55

So the highest common factor they have is 55.

HCF = 55

4 0
3 years ago
11. <br> Find the equation of the line that goes through the points (4, 4) and (8, 6).
Vladimir [108]

Answer:

4,8

Step-by-step explanation:

because the lins equation goes through in 6

6 0
2 years ago
The fuel efficiency in miles per gallon of all bmw 320i's is (approximately) normally distributed with a mean of 25 and a standa
grigory [225]
Given:
μ = 25 mpg, the population mean
σ = 2 mpg, the population standard deviation

If we select n samples for evaluation, we should calculate z-scores that are based on the standard error of the mean.
That is,
z= \frac{x-\mu}{\sigma / \sqrt{n} }

The random variable is x = 24 mpg.

Part (i):  n = 1
σ/√n = 2
z = (24 -25)/2 = -0.5
From standard tables,
P(x < 24) = 0.3085

Part (ii): n = 4
σ/√n = 1
z = (24 -25)/1 = -1
P(x < 24) = 0.1587

Part (iii): n=16
σ/√n = 0.5
z = (24 - 25)/0.5 = -2
P(x < 24) = 0.0228

Explanation:
The larger the sample size, the smaller the standard deviation.
Therefore when n increases, we are getting a result which is closer to that of the true mean.
6 0
4 years ago
You deposit $1,000 for years at an interest rate of 2.0%.If the interest is compounded guardedly.How much money would you have a
Stells [14]
Principle(P)=$1000
Rate (r)=2%=0.02
Time=t=4 years
n=no of times the interest is compounded per year=4
Amount (A)=?
Then,
A=P{(1+r/n)}^(n×t)
=1000{1+0.02/4}^(4×4)
=1000×(1.005^16)
=1000 × 1.08307115
=1083.07115
=1083.07 (approx)

Thus at the end of 4 years the amount of money will be Rs 1083.070 approximately.

Hope this helps....
8 0
3 years ago
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