We are going to consider a rectangle with length called "a" and width "b" Then we know that perimeter is the sum of both sides 2*a + 2*b = 128 And also the following equation given by the question: a = 2*b + 3 So solving the first equation: 2*(2*b+3) + 2*b = 128 4*b+6+2*b=128 6*b = 122 b = 122/6 = 61/3 Then a=2*122/6+3 = 244/6+3 = 262/6 = 131/3 Solution: Length = 131/3 Width = 61/3
Answer:
third choice
Step-by-step explanation:
Answer:
√2
Step-by-step explanation:
Solving the given expression step by step:
![\frac{\sqrt{36} }{\sqrt{18} } = \frac{6}{3\sqrt{2} }\ \ \ [\because \sqrt{36} = 6 \ and \ \sqrt{18} = 3\sqrt{2}] \\ = \frac{3 \times 2}{3\sqrt{2} } = \frac{ 2}{\sqrt{2} }= \sqrt{2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B36%7D%20%7D%7B%5Csqrt%7B18%7D%20%7D%20%3D%20%5Cfrac%7B6%7D%7B3%5Csqrt%7B2%7D%20%7D%5C%20%5C%20%5C%20%5B%5Cbecause%20%5Csqrt%7B36%7D%20%3D%206%20%5C%20and%20%5C%20%5Csqrt%7B18%7D%20%3D%203%5Csqrt%7B2%7D%5D%20%5C%5C%20%3D%20%5Cfrac%7B3%20%5Ctimes%202%7D%7B3%5Csqrt%7B2%7D%20%7D%20%3D%20%5Cfrac%7B%202%7D%7B%5Csqrt%7B2%7D%20%7D%3D%20%5Csqrt%7B2%7D)
We rationalize denominator and change it into a simpler form as soon as possible.
Answer:
see explanation
Step-by-step explanation:
Given the width is
of the length, then
y - 4 =
(2y + 6)
Multiply through by 3 to clear the fraction
3y - 12 = 2y + 6 ( subtract 2y from both sides )
y - 12 = 6 ( add 12 to both sides )
y = 18
Thus
length = 2y + 6 = 2(18) + 6 = 36 + 6 = 42 in
width = y - 4 = 18 - 4 = 14 in
Check the picture below.
notice the sides, now, on the second triangle, side 6 slants a bit more to fit in 13, on the third triangle, side 6 slants even further to fit 13 in, now, if 6 were to slant completely, it'll make a flat-line with side 5, and there will be a triangle no more.
but even if side 6 would stretch to a flat-line, 5+6 is just 11, whilst side 13 is longer than that, so no dice.