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user100 [1]
3 years ago
11

Evaluate ModifyingBelow Integral from nothing to nothing With Upper C xy dx plus left parenthesis x plus y right parenthesis dy

∫ C xy dx+(x+y)dy along the curve y equals 4 x squared y=4x2 from left parenthesis negative 3 comma 36 right parenthesis (−3,36) to left parenthesis 1 comma 4 right parenthesis (1,4). ModifyingBelow Integral from nothing to nothing With Upper C xy dx plus left parenthesis x plus y right parenthesis dy ∫ C xy dx+(x+y)dy equals = nothing ​(Type an integer or a simplified​ fraction.)
Mathematics
1 answer:
Zepler [3.9K]3 years ago
7 0

Parameterize the curve by

\begin{cases}x(t)=t\\y(t)=4t^2\end{cases}

with -3\le t\le1. Then

\displaystyle\int_Cxy\,\mathrm dx+(x+y)\,\mathrm dy

=\displaystyle\int_{-3}^14t^3\,\mathrm dt+(t+4t^2)(8t\,\mathrm dt)

=\displaystyle\int_{-3}^1(8t^2+36t^3)\,\mathrm dt=\boxed{-\frac{1936}3}

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A survey of 1,000 men and women asked, "Do you earn over $50,000 per year?" The table below shows the responses for males and fe
frutty [35]
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Income over $50,000         485        385         870
Income below $50,000        65           65        130
<span>Total                                       550        450       1,000

Probability of being male: 550/1000 = 0.55
Probability of earning over $50,000: 870/1000 = 0.87

0.55 x 0.87 = 0.4785

Probability of being male and earning over $50,000: 485/550 = 0.8818

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7 0
3 years ago
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Find the percent of decrease from 12 home runs to 9 home runs. I need this FAST!
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Step-by-step explanation:

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3 0
2 years ago
Does anyone know this
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Based on the graphs of f (x) and g(x), what must the domain of (f ⋅ g)(x) be?
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Using the concept of domain, the domain of (f.g)(x) is given by:

{x ∈ ℝ | x ≠ 3}

---------------------

  • The domain of a function is given by all possible input values, that is, <u>on a graph, all values that the x-axis assumes.</u>
  • In the graph, <u>function f assumes all real values.</u>
  • Function g is not defined for x = 3, thus, it's domain is all real values except 3.
  • Thus, the multiplication, as fg(x) = f(x) \times g(x), will also not be defined at x = 3, and the domain of the multiplication is:

{x ∈ ℝ | x ≠ 3}

A similar problem is given at brainly.com/question/4175434

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3 years ago
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pantera1 [17]
The answer should be x=4
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3 years ago
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