Answer:
Please Find the solution below
Step-by-step explanation:
Let us say the two equations are
x+y=5 --------------(A)
x-y=1 -------------(B)
Let us solve them for x and y by adding them
2x=6
x=3
Hence from (A)
3+y=5
y=2
Hence our solution is
x=3, y=2
Adding same number to equation (A) say 2 we get
x+y+2=5+2
x+y=5+2-2
x+y=5
Hence equation remains the same while adding same number to each side.
Same thing happens if we add same number to equation (B)
Hence we draw the conclusion that the solution remains the same if same number is added to each side of the original equation.
77.5%
Change to decimal:-
77.5 ÷ 100 = 0.775
775/1000
31/40
77.5% = 31/40
I’m not sure if the 2 is counted in the equation or not
Since x=4, substitute it for x in the other equation
4+3y=29
3y=25
Y=8.333333333
2(4)+3y=29
8+3y=29
3y=37
y=12.33333333
Answer:
1 x=-2.5 y = -5.5
2. x=5 y=1
Step-by-step explanation:
1) What is the solution of the given system?
5x-y=-7
3x-y=-2
Multiply the second equation by -1
-1*(3x-y)=-1(-2)
-3x +y = 2
Now add the first equation to the modified second equation
5x-y=-7
-3x +y = 2
------------------
2x = -5
Divide each side by 2
2x/2 = -5/2
x = -2.5
Now we need to find y
-3x+y =2
-3(-2.5) +y =2
7.5 +y =2
Subtract 7.5 from each side
7.5 -7.5 +y =2-7.5
y = -5.5
2) what is the solution of the given system?
5x+7y=32
8x+6y=46
Divide the second equation by 2
8x/2+6y/2=46/2
4x+3y =23
Multiply the first equation by 4
4 (5x+7y)=32*4
20x+28y = 128
Now multiply the modified 2nd equation by -5
-5(4x+3y )=-5(23
)
-20x -15y = -115
Lets add the new equations together to eliminate x
20x+28y = 128
-20x -15y = -115
---------------------
13y = 13
Divide each side by 13
13y/13 =13/13
y=1
Now substitute back in to find x
5x+7y=32
5x +7(1) =32
5x +7 =32
Subtract 7 from each side
5x+7-7 =32-7
5x =25
Divide by 5
5x/5 =25/5
x=5
