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lora16 [44]
3 years ago
9

Choose the function in which whose graph is given below

Mathematics
2 answers:
astra-53 [7]3 years ago
8 0
<h2>Answer:</h2>

The function which best describe the graph is:

                          C.   y=csc x

<h2>Step-by-step explanation:</h2>

By looking at the graph we observe that the graph repeats itself after every 2π i.e. the period of the function is 2π.

Also, we know that the function " tan x " and " cot x " have a period of π.

Hence, option: A and option: D is discarded.

Now by looking at the graph we observe that when x → 0 then the graph of the function tends to infinity

i.e. when x → 0 then y → ∞

B)

y=\sec x

when x=0

then

y=\sec 0\\\\i.e.\\\\y=1

Hence, option: B is incorrect.

So, we are left with option: C

i.e.

y=\csc x

when we plot the graph of this function we observe that it matches the given graph.

         The correct answer is:

               Option: C

Illusion [34]3 years ago
5 0
Your answer would be c
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Answer:

A. 3.25x + 13.50 ≤ 40

The number of bracelets is x. It's a variable.

The 13.50 is a constant.

The total needs to be less than or equal to 40 because that's all the money he has.

6 0
2 years ago
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Which shapes contain at least one right angle?<br><br> Select each correct answer.
Andrej [43]
1: Trapezoid
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STEP BY STEP EXPLINATION


A right angle is exactly 90 degrees, so if the pentagon has 108 degree angles, it’s not a right Angle!

The parallelogram has 107 degree angles and 73 degree angles, it’s not exactly 90.
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8 0
2 years ago
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romanna [79]

Step-by-step explanation:

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6 0
2 years ago
Suppose a football is kicked with an initial velocity of 82 ft/sec., at an angle of
satela [25.4K]

Answer:

The position P is:

P = 87\^x + 75\^y ft     <u><em> Remember that the position is a vector. Observe the attached image</em></u>

Step-by-step explanation:

The equation that describes the height as a function of time of an object that moves in a parabolic trajectory with an initial velocity s_0 is:

y(t) = y_0 + s_0t -16t ^ 2

Where y_0 is the initial height = 0 for this case

We know that the initial velocity is:

82 ft/sec at an angle of 58 ° with respect to the ground.

So:

s_0 = 82sin(58\°) ft/sec

s_0 = 69.54 ft/sec

Thus

y(t) = 69.54t -16t ^ 2

The height after 2 sec is:

y(2) = 69.54 (2) -16 (2) ^ 2

y(2) = 75\ ft

Then the equation that describes the horizontal position of the ball is

X(t) = X_0 + s_0t

Where

X_ 0 = 0 for this case

s_0 = 82cos(58\°) ft / sec

s_0 = 43.45 ft/sec

So

X(t) = 43.45t

After 2 seconds the horizontal distance reached by the ball is:

X (2) = 43.45(2)\\\\X (2) = 87\ ft

Finally the vector position P is:

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<em>Your answer is the following.</em>

<em></em>

<em>Answer = 19/50 </em>

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