Answer:
Explanation:1) Charges are:
Flat fee: 500
First 100 tickets: 20(100) = 2000
Tickets over 100: 17 ( x - 100), where x is the number of tickets.
2) Total charges: 500 + 2000 + 17(x - 100) = 2500 + 17(x - 100)
3) Average cost per ticket = total charges / number of tickets
⇒ [2500 + 17(x - 100) ] / x
4) limit as the number of tickets, x, becomes very high ⇒ x → ∞
⇒

5) Here is the demostration of the value of that limit:
2500 / x + 17x / x - 1700/x = 0 + 17 + 0 = 17
Answer:
1.92636657×10^-3
Step-by-step explanation:
This question looks quite awful coz it might be (16+81)^3/4 rather than being (16/81)^3/4....But, if it is (16/81)^3/4 the answer is 1.92636657×10^-3
hope you find it helpful....Thanks very much...
Answer:
Possible values of M are
{
14
×
1
,
14
×
2
,
14
×
4
When two or more lines are <u>parallel</u> to each other, this implies that they do not meet even extending them till <em>infinity</em>. So the <em>statement</em> justifies the construction because only <em>one</em> line <u>through</u> point C can be constructed to be <u>parallel</u> to AB.
When a <u>parallel</u> line is constructed through a <em>point</em> to a given <em>line</em>, this is the only <u>parallel</u> line that can be <em>drawn</em> to the given line. <u>Parallel</u> lines are lines that will not meet at any point. Thus, only one <u>parallel</u> line can be constructed through a <em>point</em> not to a given <em>line</em>.
The construction of a line through C that is <u>parallel</u> to line AB is justified by the given <em>statement</em> in the <em>theorem </em>since this is the only <u>parallel</u> line to line AB that can be drawn <em>through</em> the point C. Any <em>other line</em> through C would <em>intersect</em> or <em>meet</em> line AB at a point when <u>extended,</u> thus would not be <u>parallel</u> to the given line.
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