PRE-CAL HELP PLEASE (see attachment)
1 answer:
Answer:
Explanation:
1) Charges are:
Flat fee: 500
First 100 tickets: 20(100) = 2000
Tickets over 100: 17 ( x - 100), where x is the number of tickets.
2) Total charges: 500 + 2000 + 17(x - 100) = 2500 + 17(x - 100)
3) Average cost per ticket = total charges / number of tickets
⇒ [2500 + 17(x - 100) ] / x
4) limit as the number of tickets, x, becomes very high ⇒ x → ∞
⇒
5) Here is the demostration of the value of that limit:
2500 / x + 17x / x - 1700/x = 0 + 17 + 0 = 17
Explanation:
1) Charges are:
Flat fee: 500
First 100 tickets: 20(100) = 2000
Tickets over 100: 17 ( x - 100), where x is the number of tickets.
2) Total charges: 500 + 2000 + 17(x - 100) = 2500 + 17(x - 100)
3) Average cost per ticket = total charges / number of tickets
⇒ [2500 + 17(x - 100) ] / x
4) limit as the number of tickets, x, becomes very high ⇒ x → ∞
⇒
5) Here is the demostration of the value of that limit:
2500 / x + 17x / x - 1700/x = 0 + 17 + 0 = 17
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1: y=7x+5.553;
2: y=7x+7.99.
Step-by-step explanation:
all the details can be found in the attachment (the answer is marked with colour).
1) to determine f'(x);
2) to calculate the values x₀ within the given interval;
3) to calculate the values f(x₀);
4) to calculate the values of interception 'i';
5) to write the required equations using 's' and 'i'.
