Question

PRE-CAL HELP PLEASE (see attachment)

Answer 1

Answer:


$\lim_{x \to \infty} \frac{2500+17(x-100)}{x}=17$


Explanation:


1) Charges are:


Flat fee: 500
First 100 tickets: 20(100) = 2000
Tickets over 100: 17 ( x - 100), where x is the number of tickets.

2) Total charges: 500 + 2000 + 17(x - 100) = 2500 + 17(x - 100)


3) Average cost per ticket = total charges / number of tickets


⇒ [2500 + 17(x - 100) ] / x


4) limit as the number of tickets, x, becomes very high ⇒ x → ∞


⇒           $\lim_{x \to \infty} \frac{2500+17(x-100)}{x}=17$

5) Here is the demostration of the value of that limit:


2500 / x + 17x / x - 1700/x = 0 + 17 + 0 = 17