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jolli1 [7]
3 years ago
10

Rewrite the following equation in exponential form. log49 (7) =1/2

Mathematics
1 answer:
Ivahew [28]3 years ago
8 0

Answer: This should explain everything

Step-by-step explanation: https://www.algebra.com/algebra/homework/logarithm/logarithm.faq.question.149400.html

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Evaluate the integral by interpreting it in terms of areas Draw a picture of the region the integral
denis23 [38]

Answer:

Step-by-step explanation:

The picture is below of how to separate this into 2 different regions, which you have to because it's not continuous over the whole function. It "breaks" at x = 2. So the way to separate this is to take the integral from x = 0 to x = 2 and then add it to the integral for x = 2 to x = 3. In order to integrate each one of those "parts" of that absolute value function we have to determine the equation for each line that makes up that part.

For the integral from [0, 2], the equation of the line is -3x + 6;

For the integral from [2, 3], the equation of the line is 3x - 6.

We integrate then:

\int\limits^2_0 {-3x+6} \, dx+\int\limits^3_2 {3x-6} \, dx    and

-\frac{3x^2}{2}+6x\left \} {{2} \atop {0}} \right.  +\frac{3x^2}{2}-6x\left \} {{3} \atop {2}} \right.  sorry for the odd representation; that's as good as it gets here!

Using the First Fundamental Theorem of Calculus, we get:

(6 - 0) + (-4.5 - (-6)) = 6 + 1.5 = 7.5

5 0
3 years ago
Madeleine can type 3 pages in one hour. How many pages will it take her to type a 123- page report?
Maurinko [17]
It would be 41 because 123/3 =41
4 0
3 years ago
Read 2 more answers
What the value of r that makes the value true? r+(-0.14)=0.47
Anika [276]

Answer:

0.61

Step-by-step explanation:

Add 0.14 to both sides of this equation, obtaining r = 0.61.


4 0
3 years ago
Need help please!!!!
ArbitrLikvidat [17]

Given : A inequality is given to us . The inequality is 19 ≥ t + 18 ≥ 11 .

To Find : The correct option between the given ones . To write the compound inequality with integers .

Solution : The given inequality to us is 19 ≥ t + 18 ≥ 11 . Let's simplify them seperately .

\red{\tt Case\:1}

⇒ 19 ≥ t + 18 .

⇒ t + 18 ≤ 19 .

⇒ t ≤ 19 - 18 .

⇒ t ≤ 1 = 1 ≥ t . ..................(i)

\red{\tt Case\:2}

⇒ t + 18 ≥ 11 .

⇒ t ≥ 11 - 18.

⇒ t ≥ -7 . ....................(ii)

<u>On</u><u> </u><u>combing</u><u> </u><u>(</u><u>i</u><u>)</u><u> </u><u>&</u><u> </u><u>(</u><u>ii</u><u>)</u><u> </u><u>.</u>

\Large\boxed{\green{\bf \red{\longmapsto} 1 \geqslant t \geqslant -7 }}

This means that t is less than or equal to 1 but greater than or equal to (-7) .

4 0
3 years ago
Explain how you can use reasoning to compare two fractions with the same denominator
Talja [164]
When two fractions have the same denominator, you can compare which fraction is greater by just comparing the numerators.
For example, if you have 2/5 and 3/5, the denominators are the same. So you can just look at the numerators. 3 is greater than 5, so 3/5 is greater than 2/5.

The reasoning to this is that the two numbers are divided by the same number (5), so you can compare the original numbers (numerators).
7 0
3 years ago
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