Answer:
The graph intersect the y-axis at (0,4.5)
The graph intersect the x-axis at (-3.6,0)
Step-by-step explanation:
The equation is;
-4y=-5x-18
Dived every term by -4
plot using a graph tool to view the liner graph as below
Answer:
Summation of the non variable Expression within the quality sign
1/2 + 1-2x= -13/2
3/2-2x= -13/2
Step-by-step explanation:
1/2-1/3(6x-3)=-13/2
First step
Using the distributive property to simply
1/2-(6x/3)+(3/3)=-13/2
1/2 -2x +1 = -13/2
Second step
Summation of the non variable Expression within the quality sign
1/2 + 1-2x= -13/2
3/2-2x= -13/2
Third step
Isolating the variable Expression by using the addition property of equality
-2x = -13/2 - 3/2
-2x = -16/2
Fourth step
Isolating the variable by using the division property of equality
-2x = -16/2
X = -16/2 * -1/2
X = -16/-4
X= 4
Answer:
Johnny is wrong.
Step-by-step explanation:
Johnny is wrong.
A better definition would be: 
is the set of all elements that belong to at least one A or B.
So, the elements that belong to both A and B, like c and d in this exercise, also belong to .
So:
Answer:
((2 x + 1) (4 x^2 - 2 x + 1))/8
Step-by-step explanation:
Factor the following:
x^3 + 1/8
Put each term in x^3 + 1/8 over the common denominator 8: x^3 + 1/8 = (8 x^3)/8 + 1/8:
(8 x^3)/8 + 1/8
(8 x^3)/8 + 1/8 = (8 x^3 + 1)/8:
(8 x^3 + 1)/8
8 x^3 + 1 = (2 x)^3 + 1^3:
((2 x)^3 + 1^3)/8
Factor the sum of two cubes. (2 x)^3 + 1^3 = (2 x + 1) ((2 x)^2 - 2 x + 1^2):
((2 x + 1) ((2 x)^2 - 2 x + 1^2))/8
1^2 = 1:
((2 x + 1) ((2 x)^2 - 2 x + 1))/8
Multiply each exponent in 2 x by 2:
((2 x + 1) (2^2 x^2 - 2 x + 1))/8
2^2 = 4:
Answer: ((2 x + 1) (4 x^2 - 2 x + 1))/8
Jessica runs fastest because her time/second is about 10 seconds while brookes is around 12.
