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3 years ago

The first four terms of an arithmetic sequence are -11,-5,1,7. what is the equation for an

Mathematics

1 answer:

mr_godi [17]3 years ago

7 0

Answer:

y = 6x - 11

Step-by-step explanation:

An arithmetic sequence is a linear function. This means it steadily increases or decreases through addition/subtraction by a constant amount. Here the sequence grows by adding 6 each time.

-11 + 6 = -5

-5 + 6 = 1

1 + 6 = 7

etc....

Since this is linear, its equation has the form y = mx + b where m is the slope and b is the y-intercept. The slope is m = 6 and b = -11.

y = 6x - 11

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Work out 23% of 42 give your answer correct to one decimal point

kolbaska11 [484]

Answer:

the answer is 9.66 probably

Step-by-step explanation:

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3 years ago

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the sum of interior angles of a regular polygon has 540 degrees. find the measure of each interior angle of the polygon.

ss7ja [257]

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3 years ago

PC-CSIL

pav-90 [236]

The equality used is Subtraction property of equality

Option A is correct

Step-by-step explanation:

We need to identify which option best explains or justifies Step 1.

Step 1 is: $-c = ax^2 + bx$

The given equation is: $0 = ax^2 + bx + c$

To get the equation for step 1 we need to subtract c on both sides of equation i.e using subtraction property of equality

$0-c = ax^2 + bx + c-c$

$-c = ax^2 + bx$

So, The equality used is Subtraction property of equality

Option A is correct.

Keywords: Solving Quadratic Equations

Learn more about Solving Quadratic Equations at:

#learnwithBrainly

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3 years ago

All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be

Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

$A = a + (A \cap B)$

In which a is the probability that a student is proficient in reading but not mathematics and $A \cap B$ is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

$B = b + (A \cap B)$

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

$(A \cup B) + C = 1$