we have
![A(-2, 2),B(6, 2),C(0, 8)](https://tex.z-dn.net/?f=A%28-2%2C%202%29%2CB%286%2C%202%29%2CC%280%2C%208%29)
see the attached figure to better understand the problem
we know that
The perimeter of the triangle is equal to
![P=AB+BC+AC](https://tex.z-dn.net/?f=P%3DAB%2BBC%2BAC)
and
the area of the triangle is equal to
![A=\frac{1}{2}*base *heigth](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B1%7D%7B2%7D%2Abase%20%2Aheigth)
in this problem
![base=AB\\heigth=DC](https://tex.z-dn.net/?f=base%3DAB%5C%5Cheigth%3DDC)
we know that
The distance between two points is equal to
![d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28y2-y1%29%5E%7B2%7D%2B%28x2-x1%29%5E%7B2%7D%7D)
Step ![1](https://tex.z-dn.net/?f=1)
<u>Find the distance AB</u>
![A(-2, 2),B(6, 2)](https://tex.z-dn.net/?f=A%28-2%2C%202%29%2CB%286%2C%202%29)
Substitute the values in the formula
![d=\sqrt{(2-2)^{2}+(6+2)^{2}}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%282-2%29%5E%7B2%7D%2B%286%2B2%29%5E%7B2%7D%7D)
![d=\sqrt{(0)^{2}+(8)^{2}}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%280%29%5E%7B2%7D%2B%288%29%5E%7B2%7D%7D)
![dAB=8\ units](https://tex.z-dn.net/?f=dAB%3D8%5C%20units)
Step ![2](https://tex.z-dn.net/?f=2)
<u>Find the distance BC</u>
![B(6, 2),C(0, 8)](https://tex.z-dn.net/?f=B%286%2C%202%29%2CC%280%2C%208%29)
Substitute the values in the formula
![d=\sqrt{(8-2)^{2}+(0-6)^{2}}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%288-2%29%5E%7B2%7D%2B%280-6%29%5E%7B2%7D%7D)
![d=\sqrt{(6)^{2}+(-6)^{2}}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%286%29%5E%7B2%7D%2B%28-6%29%5E%7B2%7D%7D)
![dBC=6\sqrt{2}\ units](https://tex.z-dn.net/?f=dBC%3D6%5Csqrt%7B2%7D%5C%20units)
Step ![3](https://tex.z-dn.net/?f=3)
<u>Find the distance AC</u>
![A(-2, 2),C(0, 8)](https://tex.z-dn.net/?f=A%28-2%2C%202%29%2CC%280%2C%208%29)
Substitute the values in the formula
![d=\sqrt{(8-2)^{2}+(0+2)^{2}}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%288-2%29%5E%7B2%7D%2B%280%2B2%29%5E%7B2%7D%7D)
![d=\sqrt{(6)^{2}+(2)^{2}}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%286%29%5E%7B2%7D%2B%282%29%5E%7B2%7D%7D)
![dAC=2\sqrt{10}\ units](https://tex.z-dn.net/?f=dAC%3D2%5Csqrt%7B10%7D%5C%20units)
Step ![4](https://tex.z-dn.net/?f=4)
<u>Find the distance DC</u>
![D(0, 2),C(0, 8)](https://tex.z-dn.net/?f=D%280%2C%202%29%2CC%280%2C%208%29)
Substitute the values in the formula
![d=\sqrt{(8-2)^{2}+(0-0)^{2}}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%288-2%29%5E%7B2%7D%2B%280-0%29%5E%7B2%7D%7D)
![d=\sqrt{(6)^{2}+(0)^{2}}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%286%29%5E%7B2%7D%2B%280%29%5E%7B2%7D%7D)
![dDC=6\ units](https://tex.z-dn.net/?f=dDC%3D6%5C%20units)
Step ![5](https://tex.z-dn.net/?f=5)
<u>Find the perimeter of the triangle</u>
![P=AB+BC+AC](https://tex.z-dn.net/?f=P%3DAB%2BBC%2BAC)
substitute the values
![P=8\ units+6\sqrt{2}\ units+2\sqrt{10}\ units](https://tex.z-dn.net/?f=P%3D8%5C%20units%2B6%5Csqrt%7B2%7D%5C%20units%2B2%5Csqrt%7B10%7D%5C%20units)
![P=22.81\ units](https://tex.z-dn.net/?f=P%3D22.81%5C%20units)
therefore
The perimeter of the triangle is equal to ![22.81\ units](https://tex.z-dn.net/?f=22.81%5C%20units)
Step ![6](https://tex.z-dn.net/?f=6)
<u>Find the area of the triangle</u>
![A=\frac{1}{2}*base *heigth](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B1%7D%7B2%7D%2Abase%20%2Aheigth)
in this problem
![base=AB=8\ units\\heigth=DC=6\ units](https://tex.z-dn.net/?f=base%3DAB%3D8%5C%20units%5C%5Cheigth%3DDC%3D6%5C%20units)
substitute the values
![A=\frac{1}{2}*8*6](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B1%7D%7B2%7D%2A8%2A6)
![A=24\ units^{2}](https://tex.z-dn.net/?f=A%3D24%5C%20units%5E%7B2%7D)
therefore
the area of the triangle is ![24\ units^{2}](https://tex.z-dn.net/?f=24%5C%20units%5E%7B2%7D)