I don't know if we can find the foci of this ellipse, but we can find the centre and the vertices. First of all, let us state the standard equation of an ellipse.
(If there is a way to solve for the foci of this ellipse, please let me know! I am learning this stuff currently.)

Where

is the centre of the ellipse. Just by looking at your equation right away, we can tell that the centre of the ellipse is:

Now to find the vertices, we must first remember that the vertices of an ellipse are on the major axis.
The major axis in this case is that of the y-axis. In other words,
So we know that b=5 from your equation given. The vertices are 5 away from the centre, so we find that the vertices of your ellipse are:

&

I really hope this helped you! (Partially because I spent a lot of time on this lol)
Sincerely,
~Cam943, Junior Moderator
Answer:
square root of 2
Step-by-step explanation:
Sides are 1 and 1 and the hypotenuse is the longest side (opposite the right angle)
We can use pythagerouses theorem : a^2+b^2=c^2
this means that 1^2+1^2=c^2
1+1=c^2
2=c^2
c=2/sqrt
c is the square root of 2
the hypotenuse is the square root of 2
Answer:
y=0
Step-by-step explanation:
Hello!
To solve this problem and find the asymptote you must find the value of x, for which F (x) (or y) becomes infinite, for this we solve the equation for X

As you can see if Y takes a value of zero, then X would tend to be an infinitely large value so we conclude the horizontal asymptote is y = 0, I also attached the graph!
Answer:
-6<x<-9
Step-by-step explanation:
if x+9<0 and 2x>-12
x<-9
x>-6
X is smaller than -9 but greater than -6.
The solution is -6<x<-9