Please someone explain to me how did we multiply the denominator in this

5.69÷7 you can round to nearest hundredth

pogonyaev

The answer would be .81 becuase you can't round the 1 up to 2 becuase the number in the thousandths place is not above 5.
Hope this helps!!

5 0

3 years ago

Bradley estimated the height of a tree at 2.5 meters. Carla estimated that tree's height at 8 feet.

vredina [299]

Answer: 4.1 feet : 4 feet

Step-by-step explanation:

From the question, we are informed that Bradley estimated the height of a tree at 2.5 meters. Carla estimated that tree's height at 8 feet.

The conversion ratio be used to compare Bradley's and Carla's estimates of the tree's height when measured in feet goes thus:

Since 1 feet = 0.305 meters

2.5 meters will be = 2.5/0.305 = 8.2 feet

Therefore the conversion ratio will be:.

= 8.2 : 8

Reducing to lowest term will be

= 4.1 feet : 4 feet.

= 4.1 : 4

4 0

3 years ago

1/3×(9x + 3) = 3x = - 1 3

balu736 [363]

Answer:

1/3* (9x-6) = 2x+3

⇒ (1/3)(9x)- (1/3)*6 = 2x+3 (distributive property)

⇒ 3x - 2= 2x + 3

⇒ (3x-2x) -2 = (2x-2x) +3

⇒ x-2=3

⇒ x +(-2+2) = 3+2

⇒ x= 5.

Step-by-step explanation:

pls i beg u pls mark me as a brainlliest

3 0

3 years ago

For each vector field f⃗ (x,y,z), compute the curl of f⃗ and, if possible, find a function f(x,y,z) so that f⃗ =∇f. if no such f

butalik [34]

$\vec f(x,y,z)=(2yze^{2xyz}+4z^2\cos(xz^2))\,\vec\imath+2xze^{2xyz}\,\vec\jmath+(2xye^{2xyz}+8xz\cos(xz^2))\,\vec k$

Let

$\vec f=f_1\,\vec\imath+f_2\,\vec\jmath+f_3\,\vec k$

The curl is

$\nabla\cdot\vec f=(\partial_x\,\vec\imath+\partial_y\,\vec\jmath+\partial_z\,\vec k)\times(f_1\,\vec\imath+f_2\,\vec\jmath+f_3\,\vec k)$

where $\partial_\xi$ denotes the partial derivative operator with respect to $\xi$ . Recall that

$\vec\imath\times\vec\jmath=\vec k$

$\vec\jmath\times\vec k=\vec i$

$\vec k\times\vec\imath=\vec\jmath$

and that for any two vectors $\vec a$ and $\vec b$ , $\vec a\times\vec b=-\vec b\times\vec a$ , and $\vec a\times\vec a=\vec0$ .

The cross product reduces to

$\nabla\times\vec f=(\partial_yf_3-\partial_zf_2)\,\vec\imath+(\partial_xf_3-\partial_zf_1)\,\vec\jmath+(\partial_xf_2-\partial_yf_1)\,\vec k$

When you compute the partial derivatives, you'll find that all the components reduce to 0 and

$\nabla\times\vec f=\vec0$

which means $\vec f$ is indeed conservative and we can find $f$ .

Integrate both sides of

$\dfrac{\partial f}{\partial y}=2xze^{2xyz}$

with respect to $y$ and

$\implies f(x,y,z)=e^{2xyz}+g(x,z)$

Differentiate both sides with respect to $x$ and

$\dfrac{\partial f}{\partial x}=\dfrac{\partial(e^{2xyz})}{\partial x}+\dfrac{\partial g}{\partial x}$

$2yze^{2xyz}+4z^2\cos(xz^2)=2yze^{2xyz}+\dfrac{\partial g}{\partial x}$

$4z^2\cos(xz^2)=\dfrac{\partial g}{\partial x}$

$\implies g(x,z)=4\sin(xz^2)+h(z)$

Now

$f(x,y,z)=e^{2xyz}+4\sin(xz^2)+h(z)$

and differentiating with respect to $z$ gives

$\dfrac{\partial f}{\partial z}=\dfrac{\partial(e^{2xyz}+4\sin(xz^2))}{\partial z}+\dfrac{\mathrm dh}{\mathrm dz}$

$2xye^{2xyz}+8xz\cos(xz^2)=2xye^{2xyz}+8xz\cos(xz^2)+\dfrac{\mathrm dh}{\mathrm dz}$

$\dfrac{\mathrm dh}{\mathrm dz}=0$

$\implies h(z)=C$

for some constant $C$ . So

$f(x,y,z)=e^{2xyz}+4\sin(xz^2)+C$

3 0

3 years ago

A 25 foot ladder is set against the side of a house so that it reaches up 15 feet. If Damian grabs the ladder at its base and pu

lapo4ka [179]

Answer: 9.8 ft

Step-by-step explanation: did on delta math:)

6 0

2 years ago