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lapo4ka [179]
3 years ago
15

PLEASSSSSE I NEED HELP BAD HELP PLEASE

Mathematics
1 answer:
charle [14.2K]3 years ago
7 0

Answer:

See explanation

Step-by-step explanation:

Given the equation 3x-4y=12

A. Create the table of values for at least 4 points.

When x=0,

3\cdot 0-4y=12\\ \\-4y=12\\ \\y=-3

When x=2,

3\cdot 2-4y=12\\ \\-4y=12-6\\ \\-4y=6\\ \\y=-1.5

When x=4,

3\cdot 4-4y=12\\ \\-4y=12-12\\ \\-4y=0\\ \\y=0

When x=6,

3\cdot 6-4y=12\\ \\-4y=12-18\\ \\-4y=-6\\ \\y=1.5

When x=8,

3\cdot 8-4y=12\\ \\-4y=12-24\\ \\-4y=-12\\ \\y=3

Thus, the table is

\begin{array}{cc}x&y\\0&-3\\2&-1.5\\4&0\\6&1.5\\8&3\end{array}

B. Use the table of values to graph the line on the coordinate plane. Plot given points and connect them with the straight line (see attached diagram).

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Let f(x)=2x^2-2x+7 and g(x) =x^2 +9x-6. Find f(x)-g(x)
Helga [31]

Step-by-step explanation:

hi im not really sure if this is right

5 0
3 years ago
Read 2 more answers
A rope 13 meters long will just reach from the top of a flagpole to a point on the ground 12 meters from teh base of the flagpol
goldfiish [28.3K]

Answer:

the height of the flagpole is 5 meters

Step-by-step explanation:

The computation of the height of the flagpole is given below

Given that

the length of the rope is 13 meters

And, the ground would be 12 meters

Based on the above information, the height of the flagpole is

= √13^2 - √12^2

= √169 - √144

= √25

= 5 meters

hence the height of the flagpole is 5 meters

5 0
3 years ago
An item is regularly priced at $31. It is now priced at a discount of 55% off the regular price.
Alekssandra [29.7K]
17.05 I think..
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5 0
3 years ago
I need to solve this equation, when you answer i would like the steps on how you did it so that i can do problems like this one.
Alla [95]

Answer:

3(3x-1)

Step-by-step explanation:

3(2x-1)+3

3(2x-1x)

3(3x-1)

3(3x-1)

5 0
2 years ago
Two objects were lifted by a machine. One object had a mass of 2 kilograms and was lifted at a speed of 2m/sec. the other had a
OLga [1]
Sadly, after giving all the necessary data, you forgot to ask the question.
Here are some general considerations that jump out when we play with
that data:

<em>For the first object:</em>
The object's weight is (mass) x (gravity) = 2 x 9.8 = 19.6 newtons
The force needed to lift it at a steady speed is 19.6 newtons.
The potential energy it gains every time it rises 1 meter is 19.6 joules.
If it's rising at 2 meters per second, then it's gaining 39.2 joules of
     potential energy per second.
The machine that's lifting it is providing 39.2 watts of lifting power.
The object's kinetic energy is 1/2 (mass) (speed)² = 1/2(2)(4) = 4 joules.

<em>For the second object:</em>
The object's weight is (mass) x (gravity) = 4 x 9.8 = 39.2 newtons
The force needed to lift it at a steady speed is 39.2 newtons.
The potential energy it gains every time it rises 1 meter is 39.2 joules.
If it's rising at 3 meters per second, then it's gaining 117.6 joules of
     potential energy per second.
The machine that's lifting it is providing 117.6 watts of lifting power.
The object's kinetic energy is 1/2 (mass) (speed)² = 1/2(4)(9) = 18 joules.

If you go back and find out what the question is, there's a good chance that
you might find the answer here, or something that can lead you to it.

4 0
3 years ago
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