Step-by-step explanation:
hi im not really sure if this is right
Answer:
the height of the flagpole is 5 meters
Step-by-step explanation:
The computation of the height of the flagpole is given below
Given that
the length of the rope is 13 meters
And, the ground would be 12 meters
Based on the above information, the height of the flagpole is
= √13^2 - √12^2
= √169 - √144
= √25
= 5 meters
hence the height of the flagpole is 5 meters
17.05 I think..
this could be it idrk what it is
Answer:
3(3x-1)
Step-by-step explanation:
3(2x-1)+3
3(2x-1x)
3(3x-1)
3(3x-1)
Sadly, after giving all the necessary data, you forgot to ask the question.
Here are some general considerations that jump out when we play with
that data:
<em>For the first object:</em>
The object's weight is (mass) x (gravity) = 2 x 9.8 = 19.6 newtons
The force needed to lift it at a steady speed is 19.6 newtons.
The potential energy it gains every time it rises 1 meter is 19.6 joules.
If it's rising at 2 meters per second, then it's gaining 39.2 joules of
potential energy per second.
The machine that's lifting it is providing 39.2 watts of lifting power.
The object's kinetic energy is 1/2 (mass) (speed)² = 1/2(2)(4) = 4 joules.
<em>For the second object:</em>
The object's weight is (mass) x (gravity) = 4 x 9.8 = 39.2 newtons
The force needed to lift it at a steady speed is 39.2 newtons.
The potential energy it gains every time it rises 1 meter is 39.2 joules.
If it's rising at 3 meters per second, then it's gaining 117.6 joules of
potential energy per second.
The machine that's lifting it is providing 117.6 watts of lifting power.
The object's kinetic energy is 1/2 (mass) (speed)² = 1/2(4)(9) = 18 joules.
If you go back and find out what the question is, there's a good chance that
you might find the answer here, or something that can lead you to it.