Step-by-step explanation:
Let the sum of rupee be x
no of boys be y
then each boy get x/y
now if the no of boys increased by 10 each boy get x/(y+10) = (x/y)-1 => x/(y+10) = (x-y)/y .........(1)
now case 2nd if no of boys decrease by 15 each boy get x/(y-15)= (x/y) +3 => x/(y-15) = (x+3y)/y ...........(2)
Answer:
QR = 17 cm
Step-by-step explanation:
Δ RST is a 5- 12- 13 triangle with hypotenuse RT = 13 cm , then
TS = 5 cm and PT = 2 × 5 = 10 cm
So PS = 10 + 5 = 15 cm
PS is parallel to the vertical line from vertex Q and intersects the horizontal line projected from SR of length 20 - 12 = 8 cm
Using the right triangle formed calculate QR using Pythagoras' identity
QR² = 15² + 8² = 225 + 64 = 289 ( take square root of both sides )
QR =
= 17
Answer:
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