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3 years ago

PLEASE HELP me!! will give brainliest!! (:

Mathematics

2 answers:

Cloud [144]3 years ago

5 0

Answer:

The answer to your question is: Yes, x - 5 is a factor of the polynomial.

Step-by-step explanation:

To answer this question you need to divide the polynomial by the factor and if there is nothing left, they are factor.

x³ -4x² -7x +10

x -5

x² + x -2

x-5 x³ -4x² -7x +10

-x³ + 5x²

x² - 7x

-x² + 5x

-2x + 10

+2x -10

0 0 These zeros tell us that the linear

expression is a factor of the polynomial

rjkz [21]3 years ago

3 0

Hey!

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Solution:

$f(x)= \frac{x^3-4x^2-7x+10}{x-5}\\f(x)= x^2 + x - 2\\f(x)= (x^2 + x - 2)(x-5)\\f(x)= (x+2) (x-1) (x-5)$

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Answer:

$f(x) = (x+2) (x-1) (x-5)$

x - 5 is a factor of this polynomial.

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Hope This Helped! Good Luck!

You might be interested in

Which are correct representations of the inequality -3(2x - 5) < 5(2-x)? Select two options. A)x< 5

Gre4nikov [31]

Answer:

C and D or 3 and 4 0-0

Step-by-step explanation:

7 0

3 years ago

An incomplete distribution is given below:Variable You are given that the median value is 70 and the total number of items is 20

expeople1 [14]

Answer:

The missing frequencies are x = 8 and y = 43.

Step-by-step explanation:

Median Value =70

Then the median Class =60-80

Let the missing frequencies be x and y.

Given: Total Frequncy = 200 , Median = 46

$\left|\begin{array}{c|ccccccc}Value&0-20&20-40&40-60&60-80&80-100&100-120&120-140\\Frequency&12&30&x&66&y&27&14\\$Cumu.Freq&12&42&42+x&108+x&108+x+y&135+x+y&149+x+y\end{array}\right|$

From the table

$\sum f_i =149+x+y$

Here, n = 200

n/2 = 100

Lower Class Boundary of the median class, l=60

Frequency of the median class(f) =66

Cumulative Frequency before the median class, f=42+x

Class Width, h=10

$Median = l + \dfrac{\dfrac{n}{2} - c.f }{f} \times h$

$70 = 60+ \dfrac{100- 42+x }{66}\times 10\\70 = 60+ \dfrac{58+x }{66}\times 10\\70-60=\dfrac{58+x }{66}\times 10\\10*66=10(58+x)\\58+x=66\\x=66-58\\x=8$

200=149+x+y

200=149+8+y

y=200-(149+8)

y=43

Hence, the missing frequencies are x = 8 and y = 43.

8 0

3 years ago

The 11th term of an progression is 25 and the sum of the first 4 terms is 49. The nth term of the progression is 49

KIM [24]

Answer:

For 1: The first term is 10 and the common difference is $\frac{3}{2}$

For 2: The value of n is 27

Step-by-step explanation:

The n-th term of the progression is given as:

$a_n=a_1+(n-1)d$

where,

$a_1$ is the first term, n is the number of terms and d is the common difference

The sum of n-th terms of the progression is given as:

$S_n=\frac{n}{2}[2a_1+(n-1)d]$

where,

$S_n$ is the sum of nth terms

For (1):

The 11th term of the progression:

$25=a_1+10d$ .......(1)

Sum of first 4 numbers:

$49=\frac{4}{2}[2a_1+3d$ ......(2)

Forming equations:

$98=8a_1+12d$

$25=a_1+10d$ ( × 8)

The equations become:

$98=8a_1+12d$

$200=8a_1+80d$

Solving above equations, we get:

$102=68d\\\\d=\frac{102}{68}=\frac{3}{2}$

Putting value in equation (1):

$25=a_1+10\frac{3}{2}\\\\a_1=[25-15]=10$

Hence, the first term is 10 and the common difference is $\frac{3}{2}$

For 2:

The nth term is given as:

$49=10+(n-1)\frac{3}{2}$

Solving the above equation:

$39=(n-1)\frac{3}{2}\\\\n-1=26\\\\n=27$

Hence, the value of n is 27

3 0

3 years ago

Find the slope of the line passing through the points (-2, 9) and (-10, 33).

olga nikolaevna [1]

The answer the your question should be a slope of -3

6 0

4 years ago

Given two points A and B, there is only one segment that you can name: AB. With three collinear points A, B, and C, there are th

aksik [14]

Answer: 10

Imagine you have 2 slots or boxes that are empty. They represent the possible choices for the letter you pick. For example, you can place B in slot 1 and D in slot 2. There are 5 choices for slot 1 (A,B,C,D,E) and four choices for slot 2. Why 4? Because after we pick the letter for slot 1, we have one less letter to pick from. We can't reuse that letter.

Now multiply those values 5 and 4 to get 20. There are 20 different ways to pick a pair of letters from a pool of 5 total. However, order does NOT matter because the segment AB is the same as BA. Since order doesn't matter, we are doubly counting when we shouldn't. In other words, our count is two times higher than it should be. Instead of 20 pairs, it's actually 20/2 = 10 pairs. That's why the answer is 10.

The list of 10 segments are: {AB,AC,AD,AE,BC,BD,BE,CD,CE,DE}

Side note: you can use the nCr combination formula with n = 5 and r = 2 to get the same answer.

4 0

4 years ago