All categories

3 years ago

Which of the following describes the translation of the graph of y = x^2 to obtain the graph of y = -x^2 - 3?

Mathematics

2 answers:

Svetllana [295]3 years ago

4 0

Answer:

The answer to your question would be option b.

Step-by-step explanation:

-x^2 is the negative of x^2, so that is why it will reflect over the x axis, and subtracting any number from it means it will shift down. So, shift down three.

natima [27]3 years ago

3 0

The answer is B. <span>reflect over the x-axis and shift down 3</span>

You might be interested in

What is 8c squared + 7c

MariettaO [177]

(8c)^2+7c
(8c)^2=64c^2
so that..

64c^2+7c
factor out c
c(64c+7)

8 0

3 years ago

Find an equation of the circle that has center (-1, 3) and passes through (1.<br> 1)

pshichka [43]

Answer:

(x + 1)² + (y - 3)² = 8

Step-by-step explanation:

radius (r): √(1 - (-1))² + (1 - 3)² = √8 = 2√2

Formula for circle with center (h,k): (x – h)² + (y – k)² = r²

(x + 1)² + (y - 3)² = 8

3 0

3 years ago

Read 2 more answers

What is the coolest hair and eye color combination? Mine is Red hair and blue eyes... That's because I have red hair and blue ey

marysya [2.9K]

Answer:

Hi how are you doing today Jasmine

6 0

3 years ago

Read 2 more answers

Suppose a parabola has vertex (6,5) and also passes through the point (7,7). Write the equation of the parabola in vertex form.

jek_recluse [69]

Answer:

Choice B: $y = 2\, (x - 6)^{2} + 5$ .

Step-by-step explanation:

For a parabola with vertex $(h,\, k)$ , the vertex form equation of that parabola in would be:

$\text{$y = a\, (x - h)^{2} + k$ for some constant $a$}$ .

In this question, the vertex is $(6,\, 5)$ , such that $h = 6$ and $k = 5$ . There would exist a constant $a$ such that the equation of this parabola would be:

$y = a\, (x - 6)^{2} + 5$ .

The next step is to find the value of the constant $a$ .

Given that this parabola includes the point $(7,\, 7)$ , $x = 7$ and $y = 7$ would need to satisfy the equation of this parabola, $y = a\, (x - 6)^{2} + 5$ .

Substitute these two values into the equation for this parabola:

$7 = (7 - 6)^{2}\, a + 5$ .

Solve this equation for $a$ :

$7 = a + 5$ .

$a = 2$ .

Hence, the equation of this parabola would be:

$y = 2\, (x - 6)^{2} + 5$ .

4 0

3 years ago

The total claim amount for a health insurance policy follows a distribution with density function 1 ( /1000) ( ) 1000 x fx e− =

gizmo_the_mogwai [7]

Answer:

the approximate probability that the insurance company will have claims exceeding the premiums collected is $\mathbf{P(X>1100n) = 0.158655}$

Step-by-step explanation:

The probability of the density function of the total claim amount for the health insurance policy is given as :

$f_x(x) = \dfrac{1}{1000}e^{\frac{-x}{1000}}, \ x> 0$

Thus, the expected total claim amount $\mu$ = 1000

The variance of the total claim amount $\sigma ^2 = 1000^2$

However; the premium for the policy is set at the expected total claim amount plus 100. i.e (1000+100) = 1100

To determine the approximate probability that the insurance company will have claims exceeding the premiums collected if 100 policies are sold; we have :

P(X > 1100 n )

where n = numbers of premium sold

$P (X> 1100n) = P (\dfrac{X - n \mu}{\sqrt{n \sigma ^2 }}> \dfrac{1100n - n \mu }{\sqrt{n \sigma^2}})$

$P(X>1100n) = P(Z> \dfrac{\sqrt{n}(1100-1000}{1000})$

$P(X>1100n) = P(Z> \dfrac{10*100}{1000})$

$P(X>1100n) = P(Z> 1) \\ \\ P(X>1100n) = 1-P ( Z \leq 1) \\ \\ P(X>1100n) =1- 0.841345$

$\mathbf{P(X>1100n) = 0.158655}$

Therefore: the approximate probability that the insurance company will have claims exceeding the premiums collected is $\mathbf{P(X>1100n) = 0.158655}$

4 0

3 years ago