Complete question:
The growth of a city is described by the population function p(t) = P0e^kt where P0 is the initial population of the city, t is the time in years, and k is a constant. If the population of the city atis 19,000 and the population of the city atis 23,000, which is the nearest approximation to the population of the city at
Answer:
27,800
Step-by-step explanation:
We need to obtain the initial population(P0) and constant value (k)
Population function : p(t) = P0e^kt
At t = 0, population = 19,000
19,000 = P0e^(k*0)
19,000 = P0 * e^0
19000 = P0 * 1
19000 = P0
Hence, initial population = 19,000
At t = 3; population = 23,000
23,000 = 19000e^(k*3)
23000 = 19000 * e^3k
e^3k = 23000/ 19000
e^3k = 1.2105263
Take the ln
3k = ln(1.2105263)
k = 0.1910552 / 3
k = 0.0636850
At t = 6
p(t) = P0e^kt
p(6) = 19000 * e^(0.0636850 * 6)
P(6) = 19000 * e^0.3821104
P(6) = 19000 * 1.4653739
P(6) = 27842.104
27,800 ( nearest whole number)
Answer:
70 degrees
Step-by-step explanation:
Measure of arc ABC is 128 degrees, so measure of arc BC is 128-90 = 38 degrees.
Meausure of arc BCD is 102 + 38 = 140 degrees, so measure of angle A is 140/2 = 70 degrees
Answer:
(x-1)(x+9) or x^2 + 8x-9, if you simplify.
Step-by-step explanation:
Answer:
C6 greeting cards for $23.40
Step-by-step explanation:
A. 13.5/3=4.5
B. 38.25/9=4.25
C. 23.4/6=3.9
d. 32.8/8=4.1
Answer:
option-B......Answer
Step-by-step explanation:
We are given
amount taken for loan =$10000
so, P=10000
annual interest rate =18%
r=0.18
now, we can use formula
Since, it is compounded monthly
so, n=12
we can plug values
