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Paha777 [63]
3 years ago
14

A cylinder has a height of 16 cm and a radius of 5 cm. A cone has a height of 12 cm and a radius of 4 cm. If the cone is placed

inside the cylinder as shown, what is the volume of the air space surrounding the cone inside the cylinder? (Use 3.14 as an approximation of ‘pi’.)
Mathematics
1 answer:
Molodets [167]3 years ago
6 0

Answer:

653.45 cm3

Step-by-step explanation:

First calculate the volumes of both cylinders, the formula is pi x radius^2 x height.

so, big cylinder = 1256...cm3. small cylinder = 603...cm3

Then take away the large from small.

1256...-603...

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Svetlanka [38]

Answer:

80

Procedure in attached file

Hope it helps

7 0
3 years ago
Which of the following is not equivalent to 1?
cluponka [151]

Answer:

B

Step-by-step explanation:

This is because You would still have the Y value as the answer. When you raise a function to the 0 power you will ultimately get on. In this only the coefficient is being raised rather than the whole system.

6 0
3 years ago
Henry places £6000 in an account which pays 4.6% compound interest each year
aivan3 [116]

Answer:

£ 6,564.70

Step-by-step explanation:

Henry places £6000 in an account which pays 4.6% compound interest each year. Calculate the amount in his amount after 2 years

Compound Interest formula =

A = P(1 + r/n)^nt

A = Final Amounrt

P = Principal = £6,000

r = Interest rate = 4.6%

t = Time in years = 2 years

n = Compounding frequency = Yearly = 1

First, convert R percent to r a decimal

r = R/100

r = 4.6%/100

r = 0.046 per year,

Then, solve our equation for A

A = P(1 + r/n)^nt

A = 6,000.00(1 + 0.046/1)^(1×2)

A = £ 6,564.70

The amount in his account after 2 years = £ 6,564.70

7 0
3 years ago
[PLEASE ANSWER BOTH QUESTIONS] The following data points represent the number of quesadillas each person at Toby's Tacos ate. So
Fynjy0 [20]

Answer:

Part 1: Already solved.

Part 2: 1 quesadilla.

Step-by-step explanation:

Part 1: The data points given are 0, 0, 1/4, 1/2, 1/2, 1, 1, 1, 5/4, 2, and 2.

The data are already sorted from least to greatest.

Part 2: To get the interquartile range, we must know the first and third quartiles. To find those, we need to know the median of the data.

There are 11 data points, so we can cross out 5 numbers on the left and cross out 5 numbers on the right. That leaves a median of 1.

Since we know the median is 1, we can find the first quartile by finding the median of the following numbers: 0, 0, 1/4, 1/2, 1/2 (any number less than 1). There are five numbers, so cross out two numbers from the left and cross out two numbers from the right. We are left with a first quartile of 1/4.

Now that we have the first quartile, we need to find the third quartile. Since the median was actually the first "1" in the data set, the third quartile will be the median of the numbers to the right of that "1": 1, 1, 5/4, 2, 2. Cross out the leftmost two numbers, and cross out the rightmost two numbers. We are left with a third quartile of 5/4.

Now that we have both the third and first quartiles, we can find the interquartile range! The IQR is calculated by finding the third quartile minus the first quartile. 5/4 - 1/4 = 4/4 = 1.

So, your interquartile range is 1 quesadilla.

Hope this helps!

5 0
3 years ago
Read 2 more answers
-5x+10>-15 help please
nexus9112 [7]

Answer:

Step-by-step explanation:

-5x + 10 > -15 is your original equation.

You need to isolate the x variable.

Start by subtracting 10.

-5x > -25

x > 5

3 0
3 years ago
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