Answer:
the equation of the axis of symmetry is 
Step-by-step explanation:
Recall that the equation of the axis of symmetry for a parabola with vertical branches like this one, is an equation of a vertical line that passes through the very vertex of the parabola and divides it into its two symmetric branches. Such vertical line would have therefore an expression of the form:
, being that constant the very x-coordinate of the vertex.
So we use for that the fact that the x position of the vertex of a parabola of the general form:
, is given by:

which in our case becomes:

Then, the equation of the axis of symmetry for this parabola is:

Answer: B Or A
Step-by-step explanation:
It would be the f(x+3) + 2
Answer:
210
Step-by-step explanation:
JQ is 5 times the length of JK
● JQ = 5JK
JK = 42
● JQ = 5 × 42
● JQ = 210
answer:
-1
work:
y = mx+ b
so we can tell that the Y intercept is 1, so we can plug that in. ( + b is the y-intercept)
y = mx + 1
plug in some values to find the slope.
(-1, 2)
2 = -m + 1
- 1 - 1
1 = -1m
/-1 /-1
-1 = m
the slope is -1.
i hope this helps! :D