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gavmur [86]
3 years ago
7

How to find the missing angle in a triangle with tangent

Mathematics
1 answer:
LUCKY_DIMON [66]3 years ago
7 0
Notice ther "far arc, near arc" equation below

thus \bf \measuredangle C =\cfrac{\textit{far arc}-\textit{near arc}}{2}\implies 56=\cfrac{(78x+2)-x}{2}

solve for "x"

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Please help and thank you!
lukranit [14]

9514 1404 393

Answer:

  • base area: 21 ft²
  • volume 105 ft³

Step-by-step explanation:

The area of a triangle is given by the formula ...

  A = (1/2)bh

The base and height of a right triangle can be taken to be the leg lengths, since each is perpendicular to the other.

  A = (1/2)(6 ft)(7 ft) = 21 ft² . . . . base area

__

The volume is the product of the base area and the height:

  V = Bh

  V = (21 ft²)(5 ft) = 105 ft³ . . . . volume

6 0
3 years ago
0.08 ten Times as much as
Shkiper50 [21]
0.008 x10 = 0.08
Answer : 0.008
5 0
3 years ago
Read 2 more answers
Tom keeps all his favorite marbels in a special leather bag right now five red marbels four blue marbels and there yellow marble
Nezavi [6.7K]
4/12 or 1/3? I think.
6 0
3 years ago
The radius of a cylindrical gift box is ​(4x + 1​) inches. The height of the gift box is three times the radius. What is the sur
user100 [1]

Answer:

S = 128πx² + 64πx + 8π

Step-by-step explanation:

Suraface area of a cylinder is given by:

S = 2πrh + 2πr²

We know that the height is 3 times as big as the radius, hence:

h = 3r

so we can plug in the new h value and rewrite the S equation as:

S = 2πrh + 2πr²

S = 2πr(3r) + 2πr²

S = 6πr² + 2πr²

S = 8πr²

We're given in the question that the radius is ​(4x + 1​) inches, so plug that into r.

Given: r = 4x + 1​

Therefore,

S = 8πr²

S = 8π(4x + 1​)²

S = 8π(16x²+8x+1)

S = 128πx² + 64πx + 8π

8 0
3 years ago
Read 2 more answers
The Quadratic Equation c² + 6c+ 8 = 0<br><br> Show work please
Bad White [126]
The formula for the quadratic formula is x (c in this case) = (-b(+/-)√(b²-4ac))/2a
This is used for an equation in standard quadratic form: ax² + bx + c = 0
1.) Put it in the correct form, if not already in it.
Ex. c² + 6c + 8 = 0
2.) Identify each part of the equation:
a = 1 (the leading coefficient), b = 6 (the coefficient in front of the second variable), c = 8
3.) Plug in each variable answer
c = (-6(+/-)√(6²-4(1)(8))/2(1)
4.) Simplify
c = (-6(+/-)√(36-(4*8))/2
c = (-6(+/-)√(36-32))/2
c = (-6(+/-)√(4))/2
c = (-6(+/-)2)/2
*Here, the equation splits in two. It becomes:
c = (-6+2)/2 AND c = (-6-2)/2
*Simplify again:
c = -4/2 AND c = -8/2
c = -2 AND c = -4
The answers c = -2 and c = -4 would solve the given equation.
Hope this helps! :)
6 0
3 years ago
Read 2 more answers
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