We are given:
the center of the rink at the origin.
A skating path (Susan): y = 6x - x^2 - 5
Starting point of Luke = (10, -21)
Path (Luke) = quadratic eq'n with vertex at (8, -9)
Radius = 35 meters
The solution that best interprets the path of the skaters is to substitute Luke's starting point to Susan's path or set-up a quadratic equation with vertex of (8,-9) and then equate to Susan's path to solve for their intersection.
Option a. option a has an answer of x=13, while the other problems have solutions of x=5.
Answer: A)42 im pretty sure
Answer:
12
Step-by-step explanation:
skeins of yarn purchased = 11
Feets per skein = 660 feets
Total number of feets purchased = (11 * 660) = 7260 feets
To make a scarf :
1 scarf = 200 yards
Recall :
1 yard = 3 feets
Hence,
1 scarf = (200 *3) = 600 feets
Number of scarf that can be made :
Total feets of yarn / Number of feets per scarf
= 7260 / 600
= 12.1
Hence, number of scarfLee can make for shelter is 12 (nearest whole number)
Answer:
The solution is possible
Step-by-step explanation:
Given

Required
Is an output of 200, possible?
To know if it is possible or not, we start by substituting 200 for f(x)

Divide both sides by 5




Take logarithm of both sides

Apply law of logarithm

Divide both sides by log2



for f(x) = 200, x is approximately 5.32
Hence, the solution is possible