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3 years ago

What is t×3/4 for t equals 8/9

Mathematics

2 answers:

r-ruslan [8.4K]3 years ago

7 0

2/3, I googled it and used a calculator ((8/9)*(3/4)).<span />

Kamila [148]3 years ago

7 0

We are going to do 8/9*3/4: Solution: 2/3

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A 50% increase followed by 33% decrease is a greater than original less than original or same as original

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3 years ago

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2 years ago

D is between C and E, CD = x 2 , CE = 32-2x, and DE = 12x. Find CD, DE, and CE.

Gemiola [76]

Answer:

CD = 4
DE = 24
CE = 28

Step-by-step explanation:

The segment addition theorem tells you ...

CD +DE = CE

x^2 +12x = 32 -2x

Subtract the right side to put this in standard form.

x^2 +14x -32 = 0

(x +16)(x -2) = 0

x = -16 or 2

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3 years ago

A point (-7, -6) is rotated counterclockwise about the origin to map onto (-6, 7). The

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3 years ago

The curves r1(t) = 2t, t2, t4 and r2(t) = sin t, sin 5t, 2t intersect at the origin. Find their angle of intersection, θ, correc

masya89 [10]

Answer:

Therefore the angle of intersection is $\theta =79.48^\circ$

Step-by-step explanation:

Angle at the intersection point of two carve is the angle of the tangents at that point.

Given,

$r_1(t)=(2t,t^2,t^4)$

and $r_2(t)=(sin t , sin5t, 2t)$

To find the tangent of a carve , we have to differentiate the carve.

$r'_1(t)=(2,2t,4t^3)$

The tangent at (0,0,0) is [ since the intersection point is (0,0,0)]

$r'_1(0)=(2,0,0)$ [ putting t= 0]

$|r'_1(0)|=\sqrt{2^2+0^2+0^2} =2$

Again,

$r'_2(t)=(cos t ,5 cos5t, 2)$

The tangent at (0,0,0) is

$r'_2(0)=(1 ,5, 2)$ [ putting t= 0]

$|r'_1(0)|=\sqrt{1^2+5^2+2^2} =\sqrt{30}$

If θ is angle between tangent, then

$cos \theta =\frac{r'_1(0).r'_2(0)}{|r'_1(0)|.|r'_2(0)|}$

$\Rightarrow cos \theta =\frac{(2,0,0).(1,5,2)}{2.\sqrt{30} }$

$\Rightarrow cos \theta =\frac{2}{2\sqrt{30} }$

$\Rightarrow cos \theta =\frac{1}{\sqrt{30} }$

$\Rightarrow \theta =cos^{-1}\frac{1}{\sqrt{30} }$

$\Rightarrow \theta =79.48^\circ$

Therefore the angle of intersection is $\theta =79.48^\circ$ .

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3 years ago