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antoniya [11.8K]
4 years ago
13

Rewrite the equation by completing the squares x^2-x-20

Mathematics
1 answer:
yuradex [85]4 years ago
3 0

Answer:  x = ¹/₂ ± √⁸¹

                     ------------

                            2

Step-by-step explanation:

First write out the equation

x² - x - 20

Now we now write the equation by equating to 0

x² - x - 20 = 0

We now move 20 to the other side of the equation. So

x² - x    =  20,

We now add to both side of the equation square of the half the coefficient of the (x) and not (x²) which is (1) . So, the equation now becomes

x² - x + ( ¹/₂ )² = 20 + ( ¹/₂ )²

x² - ( ¹/₂ )²       = 20 + ¹/₄

( x - ¹/₂ )²       = 20  + ¹/₄, we now resolve the right hand side expression into fraction

( x - ¹/₂ )²          =  ⁸¹/₄ when the LCM is made 4

Taking the square root of both side to remove the square,we now have

x - ¹/₂               =  √⁸¹/₄

x - ¹/₂               =     √⁸¹/₂

Therefore,

                    x = ¹/₂ ± √⁸¹

                          -----------

                               2

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