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Anna71 [15]
3 years ago
6

Someone please helpppp!!no bs answers. geometry

Mathematics
1 answer:
DaniilM [7]3 years ago
6 0

Answer:

Line TB is congruent to line BR.

B is the midpoint of line TR.

Line TB plus line BR is equal to or congruent to line TR.

*wink face lol*

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The quadrilateral with the following vertices is a
Vesna [10]

Answer:

Parallelogram

Step-by-step explanation: You have to plot the points in a coordinate plane. If you do that and connect the dots you will get parallelogram.

8 0
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The center of a hyperbola is located at the origin. One focus is located at (−50, 0) and its associated directrix is represented
leva [86]

The equation of the hyperbola is : \frac{x^{2}}{48^2}  - \frac{y^{2}}{14^2}  = 1

The center of a hyperbola is located at the origin that means at (0, 0) and one of the focus is at (-50, 0)

As both center and the focus are lying on the x-axis, so the hyperbola is a horizontal hyperbola and the standard equation of horizontal hyperbola when center is at origin: \frac{x^{2}}{a^{2}}  - \frac{y^{2}}{b^{2}}    = 1

The distance from center to focus is 'c' and here focus is at (-50,0)

So, c= 50

Now if the distance from center to the directrix line is 'd', then

d= \frac{a^{2}}{c}

Here the directrix line is given as : x= 2304/50

Thus, \frac{a^{2}}{c}  = \frac{2304}{50}

⇒ \frac{a^{2}}{50}  = \frac{2304}{50}

⇒ a² = 2304

⇒ a = √2304 = 48

For hyperbola, b² = c² - a²

⇒ b² = 50² - 48² (By plugging c=50 and a = 48)

⇒ b² = 2500 - 2304

⇒ b² = 196

⇒ b = √196 = 14

So, the equation of the hyperbola is : \frac{x^{2}}{48^2}  - \frac{y^{2}}{14^2}  = 1

5 0
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Just simplify?
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Step-by-step explanation:

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