What vision abnormality occurs when light is focused behind the retina?

1 answer:

7 0

The farsightedness or hyperopia occur when light focused behind the retina. The main reason of this type of abnormality is that because of the lens and cornea may not be able to bend the light rays to focus them on the retina. Hence the light rays focused behind the retina. The other reasons of hyperopia are the small size of the eyeball which causes the decrease in the refractive power of cornea and lens. Due to this small size of the eyeball the light rays focused behind the retina.

You might be interested in

Name the tissue that water travels up from the roots to shoots in a deciduous tree.

Leviafan [203]

The tissue that water travels up from the roots to shoots in a deciduous tree is xylem.

<h3>What is xylem?</h3>

Xylem is one among the two types of transport tissue in vascular plants, the opposite being phloem.
Transport water from roots to stems and leaves is the main function of xylem, but it also transports nutrients.
The word xylem springs from the Ancient Greek word ξύλον (xylon), meaning "wood"; the best-known xylem tissue is wood, though it's found throughout a plant. The term was introduced by Carl Nägeli in 1858.
The long tracheary elements are the most distinctive xylem cells that transport water. Tracheid and vessel elements are distinguished by their shape; vessel elements are shorter, and are connected together into long tubes that are called vessels.

To learn more about xylem: brainly.com/question/12813346

#SPJ4

5 0

2 years ago

Cystic fibrosis is an autosomal recessive disorder. In one population, the frequency of affected individuals (A 2 A 2) is 0.0004

Simora [160]

Hardy Weinberg Equilibrium

Explanation:

Hardy Weinberg Equilibrium formula for allelic frequency is: $p+q=1$

Hardy Weinberg Equilibrium formula for genotypic frequency is: $p^2+q^2+2pq=1$

Here, $p$ =frequency of dominant allele

$q$ =frequency of recessive allele

$p^2$ =frequency of dominant genotype

$q^2$ =frequency of recessive genotype

$2pq$ =frequency of heterozygous genotype

frequency of affected individuals=0.0004(given)

here,affected individuals means the one's having Cystic Fibrosis and since it is recessive disease so we can write frequency of recessive genotype as: $q^2$ =0.0004