First, move 9x^2 to the right:
7y^2 = 42 - 9x^2
Then, divide 7 on both sides:
y^2 = 6 - 9/7 * x^2
To get heads: 1/2 because there are two sides to a coin.
There are 6 sides on a cube and 2 numbers are greater than 4 (5 and 6) so 2/6
Now multiply: 1/2 * 2/6 = 2/12 = 1/6
1/6 is the final answer.
When two fractions are equivalent that means that different fractions have the same number
<span><span>y = 2 + 2sec(2x)
The upper part of the range will be when the secant has the smallest
positive value up to infinity.
The smallest positive value of the secant is 1
So the minimum of the upper part of the range of
y = 2 + 2sec(2x) is 2 + 2(1) = 2 + 2 = 4
So the upper part of the range is [4, )
The lower part of the range will be from negative infinity
up to when the secant has the largest negative value.
The largest negative value of the secant is -1
So the maximum of the lower part of the range of
y = 2 + 2sec(2x) is 2 + 2(-1) = 2 - 2 = 0
So the lower part of the range is (, 0].
Therefore the range is (, 0] U [4, )
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1q+2=-6q+3+8q+4
1q+2=2q+7
<span>-2q -2q
</span>-q+2=7
<span> -2 -2
</span>-q=<span>5
-1 -1
q=-5
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