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liberstina [14]

3 years ago

9

A clothing article was originally priced at $120. It was reduced for a sale to $90. What fractional part of the original price w

as the discount?

1 answer:

NemiM [27]3 years ago

5 0

Write 90 out of 120 as a fraction-90/120. Simplify that until you can't any more and you get 3/4 of the original price.

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PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! I CANNOT RETAKE THIS!!

Rashid [163]

$x = \frac{ -2 \pm \: \sqrt{ {2}^{2} - 4 \times 1 \times 10 } }{2} \\ \\ x = \frac{ - 2 \pm 6i}{2} \\ \\ \boxed{ \red{ \huge{x = - 1 \pm \: 3i}}}$

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Leviafan [203]

Thats gonna be 3g...

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14=6n+6-2n solve for n

Anika [276]

Answer:

n=2

Step-by-step explanation:

14=6n+6-2n

Combine like terms

14 = 4n+6

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What is 6(x+4)? Show work

natulia [17]

We will use distribution

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3 years ago

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Determine whether The given segments have the same length. Justify your answer

Semenov [28]

We know the distance formula is

$\sqrt{ (x_{2}-x_{1})^2+ (y_{2}-y_{1})^2 }$

9)

Here A( -4,2) and B(1,4)

So length of AB

= $\sqrt{(1-(-4))^2+(4-2)^2} =\sqrt{5^2+2^2} =\sqrt{29}$

Also C(2,1)

Length of BC

= $\sqrt{(2-1)^2+(-1-4)^2} =\sqrt{1^2+(-5)^2} =\sqrt{26}$

So we can see that length of AB is not equal to length of BC

11.

Now AB = $\sqrt{29}$

Also C(2,-1) & D(4,4)

Length of CD

= $\sqrt{(4-2)^2+(4-(-1)) ^2} =\sqrt{2^2+5^2} =\sqrt{29}$

Yes AB = CD

5 0

3 years ago