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bearhunter [10]
3 years ago
12

A trading card increases in value by 2% each year. In 2005, it was worth $8. About how much is it worth in 2011?

Mathematics
1 answer:
Flura [38]3 years ago
5 0

So for this, we will be using the exponential equation formula, which is y=ab^x, with a = initial value and b = growth/decay. Since the value is increasing, you would add 1 and 0.02(2% in decimal form) together to get 1.02, which will be the b variable. And since we are starting in 2005 with $8 and trying to figure out the value in 2011, 8 will be the a variable and 6 will be the x variable (2011-2005=6)

With this info, our equation will be: y = 8(1.02)^6

Firstly, solve 1.02^6: y = 8(1.12616242)

Next, multiply and your answer will be (rounded to the hundreths): y = $9.01

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8 0
3 years ago
If tñ=2ñ+3, find S10​
Allisa [31]

Answer:

S_{10}=280

Step-by-step explanation:

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t_n=2n+3 ...(1)

We need to find the value of S_{10}.

Put n = 1 to find the first term.

t_1=2(1)+3=5

Put n = 2 to find the second term.

t_2=2(2)+3=7

Put n = 3 to find the third term.

t_3=2(3)+3=9

Put n = 10 to find the tenth term.

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3 0
3 years ago
Please help me I would really appreciate that.
HACTEHA [7]

Answer:

I can only do mean and median

First, you have to write it in decreasing order

1, 4, 5, 6,7,8,9,9,9,11

Now, we seperate them

1, 4, 5, 6,7,8,9,9,9,11

the two middle numbers are 7 and 8 so the median is 7.5

upper quartile: 8,9,9,9,11

lower quartile: 1, 4, 5, 6, 7

To find the mean, we have to add all the numbers and divide it by the amount of numbers. There are 10 numbers and added togetehr they are 69 so divide 69 by 10 so 6.9 for the mean and 7.5 for median

Step-by-step explanation:

7 0
3 years ago
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