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3 years ago

The area of a square garden is 209 m squared. How long is the diagonal?

Mathematics

1 answer:

DIA [1.3K]3 years ago

3 0

Answer:

$\sqrt{418}$

Step-by-step explanation:

The length of a diagonal of a square is $\sqrt{2}a$ , where a is the length of one side.

If the area of a square garden is 209m, we know that the side length must be $\sqrt{209}$ m, since the area of a square is it’s side length squared.

Now we can substitute inside the formula.

$\sqrt{2}\cdot\sqrt{209}$

When multiplying roots, the multiplication problem can simplify down to whatever is in the roots multilpied by each other.

So, $209\cdot 2 = 418$

So the length of the diagonal is $\sqrt{418}$ m.

Hope this helped!

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Find the height of an isosceles triangle with two congruent sides of length

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Answer:

119cm

Step-by-step explanation:

add 37 and 24 you get 61 and the size of a triangle no matter what is going to be 180 so then subtract 180 from 61 and get 119.

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3 years ago

25 less than twice a number is equal to the number. What is the number?

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Step-by-step explanation:

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3 years ago

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Maksim231197 [3]

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2 years ago

a cone has a volume of 6 cubic inches. what is the volume of a cylinder that the cone fits exactly inside of

ella [17]

Answer:

= 18 cubic inches

Step-by-step explanation:

The volume of a cone is given by the formula;

V = 1/3 × base area × height

While that of cylinder is given by the formula;

Volume = Base area × height

Since we need the cylinder to fit exactly inside the cone, then it means that their bases are the same and heights are the same.

Therefore;

The cone has three times less volume compared to the cylinder.

Thus;

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3 years ago

1.What are the zeros of the polynomial function?

Lorico [155]

Let's to the first example:

f(x) = x^2 + 9x + 20

Ussing the formula of basckara

a = 1
b = 9
c = 20

Delta = b^2 - 4ac

Delta = 9^2 - 4.(1).(20)

Delta = 81 - 80

Delta = 1

x = [ -b +/- √(Delta) ]/2a

Replacing the data:

x = [ -9 +/- √1 ]/2

x' = (-9 -1)/2 <=> - 5

Or

x" = (-9+1)/2 <=> - 4
_______________

Already the second example:

f(x) = x^2 -4x -60

Ussing the formula of basckara again

a = 1
b = -4
c = -60

Delta = b^2 -4ac

Delta = (-4)^2 -4.(1).(-60)

Delta = 16 + 240

Delta = 256

Then, following:

x = [ -b +/- √(Delta)]/2a

Replacing the information

x = [ -(-4) +/- √256 ]/2

x = [ 4 +/- 16]/2

x' = (4-16)/2 <=> -6

Or

x" = (4+16)/2 <=> 10
______________

Now we are going to the 3 example

x^2 + 24 = 14x

Isolating 14x , but changing the sinal positive to negative

x^2 - 14x + 24 = 0

Now we can to apply the formula of basckara

a = 1
b = -14
c = 24

Delta = b^2 -4ac

Delta = (-14)^2 -4.(1).(24)

Delta = 196 - 96

Delta = 100

Then we stayed with:

x = [ -b +/- √Delta ]/2a

x = [ -(-14) +/- √100 ]/2

We wiil have two possibilities

x' = ( 14 -10)/2 <=> 2

Or

x" = (14 +10)/2 <=> 12
________________

To the last example will be the same thing.

f(x) = x^2 - x -72

a = 1
b = -1
c = -72

Delta = b^2 -4ac

Delta = (-1)^2 -4(1).(-72)

Delta = 1 + 288

Delta = 289

Then we are going to stay:

x = [ -b +/- √Delta]/2a

x = [ -(-1) +/- √289]/2

x = ( 1 +/- 17)/2

We will have two roots

That's :

x = (1 - 17)/2 <=> -8

Or

x = (1+17)/2 <=> 9

Well, this would be your answers.

7 0

3 years ago